在Python中,__init_subclass__() 是一个特殊方法,它在子类被创建时自动调用,允许你对子类进行自定义的初始化操作。这个方法不接受任何关键字参数,这是由Python的语言规范决定的。当你遇到错误 TypeError: __init_subclass__() takes no keyword arguments 时,意味着在子类定义中不当地向 __init_subclass__ 传入...
运行时,报TypeError: write() takes no keyword arguments 我以为是write()函数不能接受两个参数,所以改成 f = open("a.txt","w") for items in txt: print(items) f.write(items+"\n") 运行时,报'gbk' codec can't encode character '\U0001f602' in position 17: illegal multibyte sequence错误...
forpageinrange(start=1, stop=8 + 1,step=1):print(page) 结果报错TypeError: range() takes no keyword arguments: 解决办法: 原因分析:range()不接受关键字参数,把start,stop,step去掉就好啦。 forpageinrange(1, 8 + 1, 1):print(page) 然后完美解决。 题外话,如果要逆序输出,有两种办法: 1、使用...
{}.get(1,default=None)这个会报错: TypeError: get() takes no keyword arguments 因为这是底层API...
Python2.7中, 使用splite报错: TypeError: split() takes no keyword arguments 因为重维护老代码,在python3.6中写的代码到python2.7出了错,原因是python2.7中split传递参数是不支持key=value这种写法,直接写split(':', 1)这样,如果写成str.split(seq=':', maxsplit=1)这样就报错,改过来就行 with open(File_...
TypeError: rfind() takes no keyword arguments Process finished with exit code1 意思是rfind()方法不接受关键字参数,而代码中又使用了关键字参数 修改为位置参数后正常运行 str1 ='sunlightn'f= str1.rfind("n", 1, 2)print(f)"D:\Program Files\Python\Python37-32\python.exe"D:/demo/str_1.py-...
ranking_names = [item.find(class_ ="views-row").get_text()foriteminrankings] File"/Users/liam/PycharmProjects/ufcrankingwebscraper/main.py", line13,in<listcomp> ranking_names = [item.find(class_ ="views-row").get_text()foriteminrankings] TypeError: find() takes no keyword arguments...
Modified10 years, 4 months ago Viewed13k times -3 gd =open("gamedata.py","rb+") gd.write(CharHealth =100) gd.close I'm receiving the error message: write() takes no keyword arguments, and I cannot figure out why. My best interpretation is that the code is trying to interpret(Char...
my_dict# ⛔️ TypeError: dict.get() takes no keyword argumentsresult=my_dict.get('name',default='') The error was caused because we passed a keyword argument to thedict.get()method. Thedict.get()method takes only positional arguments. ...
dict的get("key", 0)方法不要添加default=,删除这个写法并不影响使用逻辑,但是加上会导致报错。 d ={'key': 2, }print(d.get("key", 0)) 问题解析 如果使用下面的代码就会报错TypeError: get() takes no keyword arguments d ={'key': 2, ...