待解决 悬赏分:1 - 离问题结束还有 syntax error, unexpected '$result' (T_VARIABLE)问题补充:匿名 2013-05-23 12:21:38 语法错误,意想不到的' $结果“ ( T_VARIABLE ) 匿名 2013-05-23 12:23:18 句法错误,意想不到的‘$result’ (T_VARIABLE) 匿名 2013-05-23 12:24:58 句法错误,...
query = "INSERT INTO user VALUES ('','$name','$password');"//结果 这句最后的分号没有，PHP解析错误，添加一个结尾分号即可
str="select password from users where username=$name and password=$password";
When I save the file it displays this error : syntax error, unexpected '|', expecting variable (T_VARIABLE) By they way, I don't know if it's the right way to add the result in the response. 0 Laracasts Elite Hall of Fame
aincl Multiplier incl乘算器 [translate] aGPS是将移动站和基准站 GPS is moves stands with the datum station [translate] a轴载换算方法 Axle load conversion method [translate] asyntax error, unexpected T_STRING, expecting T_VARIABLE 句法错误,意想不到的T_STRING,期望T_VARIABLE [translate] ...
把11行变量的引号去了 result=mysql_query("SELECT*FROM cards WHERE cards=$_post['cardno']");
以上代码是变量没定义造成的，试试变量前加 var
1 Message: Undefined variable: data 0 Why am I getting an unexpected T_VARIABLE error in my Code Igniter controller? 0 Codeigniter Parse error: syntax error, unexpected T_CLASS 1 Message: Undefined variable: data - CodeIgniter 0 CodeIgniter, Message: Undefined variable, Passing d...
I am already getting the following parsing error: Parse error: syntax error, unexpected T_VARIABLE...on line 7. The simple code is as follows: <? php $pwd = $_POST['password']; $dbn = $_POST['dbname']; $hnm = $_POST['hostname']; $link_id = mysql_connect($h...