Hint:We can see that the given series in the problem follows an Arithmetic Progression (AP). We find the ${{n}^{th}}$ term of the series by using the first term and common difference of the given series. Once, we find the ${{n}^{th}}$ terms, we...
Sum of N Terms, sum of n natural numbers, sum of n square numbers and sum of n cubic numbers, formulas are available here at BYJU'S with solved examples.
)? What is the sum of first two terms? What is the second term? Similarly find the 3rd, the10th and the nth terms. 相关知识点: 试题来源: 解析 Solution: Given that,Sn = 4n - n2First term, a = S1 = 4(1) -(1)2=4-1= 3Sum of first two terms = S2= 4(2) -(2)2...
where \(a\) is the first term, \(d\) is the common difference, and \(n\) is the term number. Let's assume the middle term of the AP is \(a_2\). Then, the sum of the three consecutive terms will be: \[a_1 + a_2 + a_3 = 72\] Substituting the formula for \(a_1...
百度试题 结果1 题目If the sum of first n terms of an AP is An+Bn^2 where A and B are constants, the common difference of AP will be ( ) A. A+B B. A − B C. 2A D. 2B 相关知识点: 试题来源: 解析 D
The following formula can be used to calculate the sum of the first n terms of an arithmetic progression (AP): Sum of first n terms (Sn) = (n/2) * [2a + (n-1)d] Where: Snis the sum of the arithmetic progression's first n terms. ...
(-1/2)=3+2= 5, whend =-1/2We know, the sum of nth term of AP is;Sn=n/2[2a+(n-1)dSo, when a = 1 and d=1/2T hen, the sum of first 16 terms are;S16=16/2[2+(16-1)1/2=8(2+15/2)=76And when a = 5 and d= -1/2T hen, the sum of first 16 terms are;...
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S. et al. Beads-on-a-string, characterization of ETS-1 sumoylated within its flexible N-terminal sequence. J. Biol. Chem. 281, 4164–4172 (2006). Article CAS PubMed Google Scholar Pichler, A. et al. SUMO modification of the ubiquitin-conjugating enzyme E2–25K. Nature Struct. Mol. ...
The sum of first nn terms of an AP is given by Sn=4n2+nSn=4n2+n. Find that APAP. AcademicMathematicsNCERTClass 10 Given: Sn=4n2+nSn=4n2+n To do: We have to find the AP. Solution: Let us take sum upto 1 term S1=4(1)2+(1)=4+1=5S1=4(...