＝10(1－10ⁿ)/(1－10)－n 所以 S＝10a(10ⁿ－1)/81－na/9 。
int main(){ long a,n,i,j,s;scanf("%ld",&a);scanf("%ld",&n);for(i=1,j=1,s=0;i<=n;i++,j=j*10+1)s+=j;s*=a;printf("%ld\n",s);return 0;}
Free GST is used as a negative control. b Schematic diagram of the SUMO-dependent dissociation assay showing the release into the supernatant of His-FMRP from the immobilized sumoylated GST-FMRP fraction. c In vitro sumoylation assay on immobilized GST-FMRP (1–160 aa). d In vitro sumoy...
简介:7.求sum=a+aa+aaa+···+a···a(n个a),其中a和n由键盘输入 #include <iostream>using namespace std;int main(){int n,a,sum=0;cout<<"please input n and a:"<<endl;cin>>n>>a;for(int i=1;i<=n;i++){sum+=a;a=a+10*a;//不断赋值替换之前的数值}cout<<sum<<endl;re...
求s=a+aa+aaa+aaaa+aa...a的值,其中a是一个数字。例如2+22+222+2222+22222(此时共有5个数相加),几个数相加有键盘控制。 #include int main() { int a, n; printf("请输入a和n:"); scanf("%d %d", &a, &n); int sum = 0, term = a; ...
Translesion polymerase eta (polη) was characterized for its ability to replicate ultraviolet-induced DNA lesions that stall replicative polymerases, a process promoted by Rad18-dependent PCNA mono-ubiquitination. Recent findings have shown that polη also acts at intrinsically difficult to replicate sequ...
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求Sn=a+aa+aaa+...+aa...a(n个a)之值,其中a是一个数字,n表示a的位数,例如:2+22+222+2222+22222(此时n=5)n由键盘输入.#include#includevoid main(){double a;int i,k,sum,n;scanf("%d",&n);sum=0,i=1,k=2;do{sum=sum+k;i=i*10;k=k+2*i;i=pow(10
A: Within 15 days after receiving your advance payment. The specific delivery time depends on the items and the quantity of your order. Q7. What is your sample policy? A: We can supply the free sample battery, but the customers have to pay the courier cost. ...
Sn=a+aa+aaa+aaaa+aa...a/*int a,n,Sn,sum;printf("please input a,n:\n");scanf("%d,%d",&a,&n);if(n9||a 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 定义等比数列公公式,aa/a=11=q,for(i=1;i 解析看不懂?免费查看同类题视频解析查看解答...