在这段代码中,我们使用了变量a和n来存储从键盘输入的值。然后,通过for循环从1到n进行迭代计算每一项,并将它们累加到sum中。最后,输出计算结果sum。当输入a=2和n=4时,运行程序得到输出为sum=2468。 首先,明确题目要求计算数列sum=a+aa+aaa+aaaa+...(共n项)的和。我们需要从键盘上输入变量a和n的值。...
int main(){ long a,n,i,j,s;scanf("%ld",&a);scanf("%ld",&n);for(i=1,j=1,s=0;i<=n;i++,j=j*10+1)s+=j;s*=a;printf("%ld\n",s);return 0;}
a(n个a)指的是一个n位数,各数位上都是a么?该求和公式可以用公式计算如下:设第n项为:An=aaa…a(n个a)=a×111…1(n个1)=a×(10ⁿ-1)/9=a/9×(10ⁿ - 1)则前n项求和为:Sn=A1+A2+…+An=a/9×[(10¹ - 1)+(10² - 1)+…+(10ⁿ...
简介:7.求sum=a+aa+aaa+···+a···a(n个a),其中a和n由键盘输入 #include <iostream>using namespace std;int main(){int n,a,sum=0;cout<<"please input n and a:"<<endl;cin>>n>>a;for(int i=1;i<=n;i++){sum+=a;a=a+10*a;//不断赋值替换之前的数值}cout<<sum<<endl;re...
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temp=0;while(i<=n){ temp=(10^(i-1))*a+temp;sum=sum+temp;i=i++;} 另外,有^个运算符吗,没有的话,只要换成pow(n,m)函数就可以了
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We propose that the K122/142R mutant of Prdx6 in the form of a TAT-fusion protein may be an easily applicable intervention for pathobiology of cells related to aberrant Sumoylation signaling in aging or oxidative stress. Cell Death and Disease (2017) 8, e2525; doi:10.1038/cddis.2016.424;...