问4x4SudokuSolver在C代码中不会产生任何输出EN我正在尝试制作一个4x4 Sudoku解算器，但我不明白为什么代...
classSolution {public:voidsolveSudoku( vector<vector<char> > &board ) {struct{shorto;shortv; } b[81] = {0};shortr[9], c[9], s[9];for(inti =0; i <9; ++i ) r[i]= c[i] = s[i] =0x01ff;//get valid digits for each row, column and squarefor(inti =0; i <81; ++i...
expValueSet = exceptValueSet(board,i,j); for (char c='1';c<='9';c++)//possible char { //cout<<" i is "<<i<<" j is "<<j<<" char is "<<c<<endl; if(expValueSet.find(c)==expValueSet.end()) { if (testUnique(board,i,j,c)) { //cout<<" in test Unique "<<en...
从C到Python的Sudoku Solver的问题 我最近在C中写了一个Sudoku Solver来练习编程。完成后,我决定在Python中编写一个等效的程序,以便在语言和更多的实践之间进行比较,这就是问题所在的比较。似乎是一个全局变量(sudokuposibities [] [] [] [])在循环中声明时声明在循环中不可用。我尝试了添加打印语句进行调试,似...
37. Sudoku Solver 借鉴了网上一片博文,主要思想就是回溯,每次插入先用isvalid判断是否合理,合理则插入,如果在之后的solver中返回false,则回溯,将board[i][j]重新改为’.’ bool isvalid(vector<vector<char>> board,int i,int j,char c) { for (int k = 0; k < 9; ++k) {...
LeetCode Sudoku Solver 数独C++程序 Sudoku Solver Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character'.'. You may assume that there will be only one unique solution. A sudoku puzzle......
本次版本实现了 用C++实现的数独解题程序 SudokuSolver 2.3 及实例分析 里发现的第三个不完全收缩 grp 算法 thirdGreenWorld。 CQuizDealer 类声明部分的修改 class CQuizDealer { public: ... 1. 2. 3. 4. void run(ulong tilsteps = 0);
37. Sudoku Solver 技术标签: LeetCode C++ 算法题目: 解答: 是很久以前做的了,代码有点长。。有空要去重新改造下。 简单的思路是这样的: 建立一个9*9的数独可选数集,每个集合包含1-9九个数 根据已有数独数据,如果是确定的数据,将集合数修改为只包含一个数 根据数独的已有数,对行、列、中等格的9个数...
seen or (c, y) in self.seen or (x/3, y/3, c) in self.seen: return False self.seen.add((x, c)) self.seen.add((c, y)) self.seen.add((x/3, y/3, c)) return True def dfs(self,board): for i in range(9): for j in range(9): if board[i][j] == '.': for ...
public class sudokuSolver { static boolean solve(int[][] board) { int n = board.length; int row = -1; int col = -1; boolean emptyLeft = true; // this is how we are replacing the r,c from arguments for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++)...