(struct ListNode)); //创建虚拟的头结点 struct ListNode* p3 = ptemp; //本质:改变两个链表的指针走向 while (p1!=NULL && p2!=NULL) { if(p1->val > p2->val) { p3->next = p2; p2 = p2->next; p3 = p3->next; } else { p3->next = p1; p1 = p1->next; p3 = p3->next; }...
struct ListNode* sortInList(struct ListNode* head ) { int i=0, count=0, num=0; struct ListNode *p, *q, *tail; p = head; while (p->next != NULL) { count++; p = p->next; } for (i=0; i<count-1; i++) { num = count - i - 1; q = head->next; p = q->next;...
(struct ListNode* head, int m, int n ) { // write code here struct ListNode*prev=NULL; struct ListNode*next=NULL; struct ListNode*phead=head; struct ListNode*reverseBegin=NULL; struct ListNode*reverseEnd=NULL;//define struct,define as NULL int i=1; if(NULL==head||NULL==head->next||...
struct ListNode *reverseList(struct ListNode *head) { if(head == NULL) { returnNULL; } if(head->next == NULL) { returnhead; } struct ListNode *reversedHead = NULL; struct ListNode *prevNode = NULL; struct ListNode *currentNode = head; while(currentNode != NULL) { struct ListNode *...
listNode *head; listNode *tail; void *(*dup)(void *ptr); void (*free)(void *ptr); int (*match)(void *ptr, void *key); unsigned long len; } list; typedef struct listNode { struct listNode *prev; struct listNode *next; void *value; ...
试写一个算法,实现单链表的就地逆置,即利用原表的存储空间将线性表逆置为 单链表结点的类型定义如下: typedef struct node { /*结点类型定义*/ Datatype data; /*结点的数据域*/ struct node *next; /**结点的指针域*/ } ListNode; 相关知识点: 试题来源: 解析...
include #include #define MAX_WEIGHT 100typedef int element;typedef struct ListNode {element data;struct ListNode *link;} ListNode;typedef struct ListNode *LinkedListType;void init(ListNode **list){*list = NULL;}int get_length(ListNode **list){ListNode *p = *list;int count = 0;...
typedef struct node2{int vertexinfo;glinklistnode *firstarc;}glinkheadnode; void adjmatrixtoadjlist(gadjmatrix g1[ ],glinkheadnode g2[ ]) { int i,j; glinklistnode *p; for(i=0;i<=n-1;i++) g2[i].firstarc=0; for(i=0;i<=n-1;i++) for(j=0;j<=n-1;j++) ...
typedefstructnode2{intvertexinfo;glinklistnode*firstarc;}glinkheadnode; voidadjmatrixtoadjlist(gadjmatrixg1[],glinkheadnodeg2[]) { inti,j;glinklistnode*p; for(i=0;i<=n-1;i++)g2[i].firstarc=0; for(i=0;i<=n-1;i++)for(j=0;j<=n-1;j++) ...
LeetCode报错runtime error:member access within null pointer of type struct ListNode 在for循环中p指针在经过一个循环后P指针位置在NULL,所以在对q指针赋值时是用NULL空地址赋值,所以提示出错。 因此在while循环前加上判断P指针是否为NULL就可以解决。*p=head,head是指向第一个链表数据。......