String::size_type n1 = str.find_first_of( chars,0); vs.push_back( str.substr( n0, n1 ) );while( n1 != String::npos ) { n0 = n1+1; n1 = str.find_first_of( chars, n0 );if( n1 != String::npos ) vs.push_back( str.substr( n0, n1-n0 ) );elsevs.push_back( str.s...
std::string::find_first_of C++98 C++11 string (1) size_t find_first_of (const string& str, size_t pos = 0) const; c-string (2) size_t find_first_of (const char* s, size_t pos = 0) const; buffer (3) size_t find_first_of (const char* s, size_t pos, size_t n) ...
size_t found = str.find_first_of(characters); if (found != std::string::npos) { std::cout << "找到了指定字符 '" << str[found] << "' 在位置 " << found << std::endl; } else { std::cout << "没有找到指定字符" << std::endl; } return 0; } ``` 输出结果: ``` 找...
find返回完全匹配的字符串的的位置; find_first_of返回被查匹配字符串中某个字符的第一次出现位置。 View Code
s.find_first_of(sub), s.find_first_not_of(sub), s.find_last_of(sub), s.find_last_not_of(sub) 这四个函数,查找s中含有sub中任意字母的索引。 2. 如果没有查询到,则返回string::npos,这是一个很大的数,其值不需要知道。 特别注意: ...
Following is the syntax for std::string::find_first_of() function. size_tfind_first_of(conststring&str,size_t pos=0)constnoexcept;orsize_tfind_first_of(constchar*s,size_t pos=0)const;orsize_tfind_first_of(constchar*s,size_t pos,size_t n)const;orsize_tfind_first_of(charc,size...
The use of find_first_of() function in C++ is to find the first occurrence of a sequence of characters in a target string. A particular sub-string may occur more than once. So, the job of find_first_of() function is to find the first occurrence of that p
c++ string 之 find_first_not_of 源码 2017-07-17 20:23 −一:实现之前先说一所find_first_not_of姊妹函数() (1)find_first_of(string &str, size_type index = 0):(find_first_of的实现例如以下链接:find_first_of的源码) ... wzjhoutai ...
4、Size_t find(const char c,size_t pos = 0) const; 示例:Str1.find(‘u’)//从str1中查找’u’字符,如果找到了就返回他的位置 find_first_of()函数原型 1、Size_t find_first_of (const string &str,size_t pos = 0) const; 2、Size_t find_first_of (const char *s,size_t pos = ...
intfind_first_of(constchar*s,intpos,intn)const; intfind_first_of(conststring&s,intpos=0)const; //从pos开始查找当前串中第一个在s的前n个字符组成的数组里的字符的位置。查找失败返回string::npos intfind_first_not_of(charc,intpos=0)const; ...