-> std::future<typename std::result_of<F(Args...)>::type>; ~ThreadPool(); private: // 消费者线程 std::vector< std::thread > workers; //任务队列 std::queue< std::function<void()> > tasks; //互斥量 std::mutex queue_mutex; std::condition_variable condition; //停止信号,如果为t...
假设我有一个返回std::vector的函数,我想异步调用它。 std::vector<int> foo(int n); int main() { auto future_vector = std::async(foo, 999); // ... other stuff // Questions are all about this: auto actual_vector = future_vector.get(); // ... do stuff with actual_vector ... ...
然后,我们创建了一个包含4个任务的vector,并使用std::async函数将每个任务提交到线程池中。每个任务返回一个std::future<int>对象,代表了异步操作的结果。然后遍历所有的std::future对象,并通过调用get()函数获取结果。注意,调用get()函数会阻塞当前线程,直到结果就绪为止。最后,将每个任务的计算结果打印到终端。 复...
{public:intmul(intx,inty) {returnx *y; } };intmain() { ThreadPool pool(5); std::vector<std::future<int>>results;//任务:lambda表达式for(inti =0; i <10; ++i) { std::future<int> fut = pool.commit([i] {returni *i;}); results.push_back(std::move(fut)); }//任务:类成...
#include<vector> #include<algorithm> #include<numeric> #include<future> template<typenameRandomIt> intparallel_sum(RandomIt beg, RandomIt end) { autolen = end - beg; if(len <1000) returnstd::accumulate(beg, end,0); RandomIt mid = beg...
int main() { thread th[10]; for (int i = 0; i < 10; i++) th[i] = thread(countnumber, i, 100000000); for (int i = 0; i < 10; i++) th[i].join(); return 0; } 你的输出有可能是这样 Thread 2 finished!Thread 3 finished!
future 模板中需要的东西是表明通信信道中没有数据被传递的一个类型。这个类型就是void。检测任务使用std...
std::cout<<"Thread 2 received the signal"<< result2.get().count() <<"ms after start."<<endl;//1.2 用容器保存std::shared_future。vector<std::shared_future<int>>vec; auto fut1= std::async(std::launch::async, [](inta,intb) {returna + b;},2,3); ...
(std::launch::async, write_log, log);}int main() {std::vector<std::future<void>> futures;futures.push_back(log_async("Start program"));// 执行其他任务...futures.push_back(log_async("End program"));// 等待所有异步日志任务完成for (auto& future : futures) {future.get();}return ...
#include <iostream>#include <vector>intmain(){// Create a vector containing integersstd::vector<int>v={8,4,5,9};// Add two more integers to vectorv.push_back(6);v.push_back(9);// Overwrite element at position 2v[2]=-1;// Print out the vectorfor(intn:v)std::cout<<n<<'...