解决方案一:lambda functions structB{vector<int>pos={0,4,2,5,3};voiddemo(){vector<int>a={2,3,1,0,4};sort(a.begin(),a.end(),[&](intx,inty){returnpos[x]<pos[y];});for(intx:a)printf("%d ",x);}}; 直接使用 lambda 函数,引用捕获this->pos进行访问。关于 lambda 函数的更多...
Would std::sort ever compare an object with itself? I'm not talking about two distinct, equal-valued objects, but rather this == &that. The container being sorted is a std::vector. I've never seen this, but a coworker says he is. NB: I can't post sa
sort()的重载版本允许在容器内部直接进行排序，只需指定容器的迭代器和比较函数。同样，用户可以指定比较函数的类型，以适应不同数据的排序需求。对于数组，sort()的另一个版本接受数组名、数组长度和比较函数，如："a is test this world hello" 和 "5 4 3 2 1"。总结来说，std::sort()提供了...
一般用的都是快速排序，最好、正常和平均时间复杂度都为O(nlog2n)，2为底的对数，最坏情况就是数据已经或者近乎有序，当然就是O(n^2)了
This can either be a function pointer or a function object. 引自---cplusplus.com 实验: 源码: #include<iostream>#include<vector>#include<algorithm>using namespacestd;boolcomp1(inta,intb){returnb>a; }boolcomp2(inta,intb){returna>b; ...
class中函数的this指向 定义一个基础的类 class Person { constructor(name = '杜恒') { this.name = name } speak() {...console.log(this); } } 将上面的类实例出一个对象p,并调用p的speak方法 const p = new Person() p.speak() // Person {name...: "杜恒"} 上面的打印结果显...
Run this code #include <algorithm>#include <array>#include <functional>#include <iostream>#include <string_view>intmain(){std::array<int,10>s{5,7,4,2,8,6,1,9,0,3};autoprint=[&s](std::string_viewconstrem){for(autoa:s)std::cout<<a<<' ';std::cout<<": "<<rem<<'\n';}...
{ x_index_ += x; y_index_ += x; return *this; } Iterator& operator-=(int x) { x_index_ -= x; y_index_ -= x; return *this; } Iterator operator+(int x) { Iterator tmp(*this); tmp += x; return tmp; } Iterator operator-(int x) { Iterator tmp(*this); tmp -= x;...
// By Zereo 04/22/13 #include <iostream> #include <algorithm> #include <vector> #include <string> using namespace std; int main() { // Warning this type of initialization requires a C++11 Compiler vector<int> intVec = {56, 32, -43, 23, 12, 93, 132, -154}; vector<string> st...
How can I make this construction valid? It still gives me error about no matching function std::sort(...). I made a little search and wrong thing is probably the predicate... template <typename TT Polygon<T:: Height() const { class BinPred : public std::binary_fun ction< Vector2D<...