std::bitset<8> binary("10101010"); // 假设有一个8位的二进制数 int start = 2; int end = 5; // 创建掩码 std::bitset<8> mask = (1<<(end+1)) - (1<<start);//(1 << (end - start + 1)) - 1; std::cout << mask << std::endl; // 提取目标位 std::bitset<8> extrac...
#include <iostream> #include <bitset> int main() { std::bitset<8> b(42); std::cout << b.to_string() << '\n' << b.to_string('*') << '\n' << b.to_string('O', 'X') << '\n'; } 输出: 00101010 **1*1*1* OOXOXOXO 参阅 ...
intbad(){uint64_tflags;puts("---bad---\n");printf("%d:%d\n",0,0);/* b0a[0].sho...
typedef std::bitset<10> B; typedef std::pair<int,int> PII; const int n=9; B h[n],l[n],g[n]; int a[n][n]; const int s[n][n]={ {6,6,6,6,6,6,6,6,6}, {6,7,7,7,7,7,7,7,6}, {6,7,8,8,8,8,8,7,6}, {6,7,8,9,9,9,8,7,6}, {6,7,8,9,10...
#include <bitset>#include <cassert>#include <cstddef>#include <iostream>intmain(){typedefstd::size_tlength_t, position_t;// 提示// 构造函数:constexprstd::bitset<4>b1;constexprstd::bitset<4>b2{0xA};// == 0B1010std::bitset<4>b3{"0011"};// C++23 起也可以为 constexprstd::bitset...
int x = 0, f = 1; char ch = getchar(); for (; !isdigit(ch); ch = getchar()) if (ch == '-') f = -1; for (; isdigit(ch); ch = getchar()) x = (x << 1) + (x << 3) + (ch ^ 48); return x * f; ...
#include <iostream>#include<bitset>#include<string>usingnamespacestd;intmain(){//bitset<n> b;//b有n位,每位都为0bitset<16>bitvec; cout<< bitvec <<endl;//bitset<n> b(u);//b是unsigned long型u的一个副本bitset<16> bitvec2(0xffff); ...
#include <iostream> #include <bitset> int main() { std::bitset<4> b; std::cout << b << "\n"; std::cout << b.flip(0) << '\n'; std::cout << b.flip(2) << '\n'; std::cout << b.flip() << '\n'; } 输出: 0000 0001 0101 1010参阅...
#include <iostream> #include <bitset> int main() { std::bitset<8> b(42); std::cout << "Bitset is " << b << '\n'; b.reset(1); std::cout << "After b.reset(1): " << b << '\n'; b.reset(); std::cout << "After b.reset(): " << b << '\n'; } 输出: ...
for (int index = 0; index != 32; index += 2) bitvec[index] = 1; 上面的循环把bitvec中的偶数下标的位都置为1。 除了用下标操作符,还可以用set、test和reset操作来测试或设置给定二进制位的值: // equivalent loop using set operation