即惰性初始化（lazy initialization）。自 C++11 起，局部static变量的初始化是线程安全的，保证多个线程...
静态变量需要在.cpp初始化,否则报错连接错误, 对于原始数据, int, double, … simple.h classSimple { public: Simple(void); ~Simple(void); staticintGetInt(void); private: staticint_i; }; simple.cpp intSimple::GetInt(void) { return_i; } 连接出错: error LNK2001: unresolved external symbol "...
```c // The IA64/generic ABI uses the first byte of the guard variable. // The ARM EABI uses the least significant bit. // Thread-safe static local initialization support. #ifdef __GTHREADS namespace { // static_mutex is a single mutex controlling all static initializations. // This...
静态变量需要在.cpp初始化,否则报错连接错误, 对于原始数据, int, double, … simple.h classSimple { public: Simple(void); ~Simple(void); staticintGetInt(void); private: staticint_i; }; simple.cpp intSimple::GetInt(void) { return_i; } 连接出错: error LNK2001: unresolved external symbol "...
Is the following code thread safe, during static variable initialization? Is there any better way to static initialize stringlist, instead of using a seperate static function (init)? Although the initialization shall happen before main function (Hence, there can be no threads to simultaneous access...
// Control access to the initialization expression. Only one thread may leave // this function before the variable has completed initialization, this thread // will perform initialization. All other threads are blocked until the // initialization completes or fails due to an exception. ...
(vlog-2244) Variable 'cnt' is implicitly static. You must either explicitly declare it as static or automatic # or remove the initialization in the declaration of variable. 上述代码仿真结果为: 代码语言:javascript 代码运行次数:0 复制Cloud Studio 代码运行 # @1 def_cnt = 1 # @2 def_cnt =...
If control enters the declaration concurrently while the variable is being initialized, the concurrent execution shall wait for completion of the initialization.8 也就是说线程B执行到正在线程A中初始化的静态变量时,要等待完成。这规定了构造函数的锁定等待特性。
Convert static variable to a constexpr. (NVIDIA#2471) Browse files Make this static data structure constant for efficiency and to eliminate an initialization ctor. Signed-off-by: Eric Schweitz <eschweitz@nvidia.com>main (NVIDIA/cuda-quantum#2471) ...
9Solving the "Static Initialization Order Fiasco" SIOF是存储时期为 static 的这类数据在跨 TUs 时相互依赖所导致的问题,因为不同 TUs 中的这些数据初始化顺序没有规定,引用的数据可能还没初始化。 因此全局变量、静态变量、静态成员变量都可能会引起这个问题。