x=2±2√32 x=1±1√3 4. To rationalize the denominator: x=1±√33 Thus, the solutions for the second equation are:x=1+√33,x=1−√33 Summary of Solutions:1. For 3x2−4x+203=0: x=23+4i3,x=23−4i3 2. For x2−2x+23=0: x=1+√33,x=1−√33 Show More ...
Solve the quadratic equation. 3x^2 + 2x Solve for x in the expression using the quadratic formula. 3x^2 + 29x - 4.7 = 0. Solve the following quadratic equations a) 3x^2 + 5x + 2 = 0 \\b) 6x^2 - x - 15 = 0 How do you solve -3x^2 - 5 = 22? How do you sol...
We are given the equation 3x2−4x=4. We want to solve the given equation. In order to solve the given equation, we need to use the...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a question Our experts can answer your tough ...
代码运行次数:0 运行 AI代码解释 1>>lp=mxlpsolve('make_lp',0,4);2>>mxlpsolve('set_verbose',lp,3);3>>mxlpsolve('set_obj_fn',lp,[1,3,6.24,0.1]);4>>mxlpsolve('add_constraint',lp,[0,78.26,0,2.9],2,92.3);5>>mxlpsolve('add_constraint',lp,[0.24,0,11.31,0],1,14.8);6>>m...
y=3x2-4 (1) y=2x+3 121 0=(3x2-4)-(2x+3)(2)-(1) This equation simpoifes to 0=3x^2-2x-7 which dass not factorise, so we need to use the quadratic formula to find the two possible ualces of x. x=(-b±√(b^2-4ac))/(2a)=\frac(-(-2)±√((22)^2-48*(-7))...
(3) x=2 (4) x=−32 or x=52 . (1) ①x+2=4−x x=1 ②x+2+4−x=0, no solution. So, x=1. (2) |3x−2|=|4−8x| ①3x−2=4−8x x=611 ②3x−2+4−8x=0 x=25 So, x=611 or x=25. (3) ①x⩾−92 2x+9=7x−1 x=2 ②x<−92 ...
Example 2: x² + 2x + 1 = 0 a = 1, b = 2 and c = 1 Δ = b² - 4ac Δ = 2² - 4.1.1 = 4 - 4.1 Δ = 4 - 4 = 0 x = -b ±√Δ2a x = -2 ±√02.1 x = -2 ±√02 Δ = 0, meaning that x₁ = x₂ = x. x = -22 = -1...
...为了解决这个问题,我们从 2x + 3X 开始。这与说 5x 相同。我们不需要将 X 加在一起,只需将乘以 x 的数字相加即可。...所以等式现在看起来像这样: 5x = 5 + 4x 下一步是获取等号一侧的所有 x。为此,我们需要从等式右侧删除 4x,并将其弹出到另一侧,以使该问题易于解决。
We are given the equation 3x+2(5x+4)=47. We want to solve the equation. So, we have: Solution: $$\begin{align}\ 3x + 2(5x + 4)...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a question Our experts can answer your tough...
Solve.1) √(2x+3)-3=02√(5x+1)-4=0 3) √(6x-5)-x=04)√(x+2)-√x=2 5) 3+x=√(6x+13)6)x-1=√(7-x) 7 √(3-3x)-1=2x8)√(2x+2)=3+√(2x-1) 9) √(4x+5)-√(x+4)=210√(3x+4)-√(x+2)=2 11) √(2x+4)-√(x+3)=112√(7x+2)-√(...