For the function f(x) = sin(x) + cos(x), the maximum value of the function in the interval [0, 2π] is: A. √2 B. 1 C. 2 D. -√2 相关知识点: 试题来源: 解析 A。f(x) = √2sin(x + π/4),在区间 [0, 2π] 中,最大值为 √2。
Find both the maximum value and the minimum value of 3 x^4-8 x^3+12 x^... 07:56 At what points in the interval [0,2 pi], does the function sin 2 x att... 10:21 What is the maximum value of the function sin x+cos x ? 04:59 Find the maximum value of 2 x^3-24 x+...
The maximum slope of the curvey=−x3+3x2+9x−27is View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep, NEET preparation and CBSE, UP Board, Bihar Bo...
x = 1, 4x2+ 2x – 1 = 0 We know that -1 ≤ sin ≤ 1, where sine is maximum at 90 degrees. Thus, sin 18 value will be less than 1. So, x = 1 cannot be accepted. Now, 4x2+ 2x – 1 = 0 Using quadratic formula,
主题 代数输入 三角输入 微积分输入 矩阵输入 sin(x)=cos(x) 求解x 的值 x=πn1+4π n1∈Z 图表
Maximum value of 5sinx−12cosx+1 https://math.stackexchange.com/questions/2657921/maximum-value-of-5-sin-x-12-cos-x-1 Note that we have the maximum value for x−67.4°=90° indeed for x−67.4°=270° we have that sin=−1 is minimum. How do you solve sinx−2cosx...
When sin is zero, then the angle is zero, so there is no opening. The maximum opening of the angle happens when sin = 1, which occurs at 90o. What is sin of 1? That question may seem as an innocent one, but it often times lead to confusion. In formal Math, all trigonometric fu...
This takes the sin and cos algorithms from Optimized Routines under MIT license, and converts them to Numpy intrinsics. The routines are within the ULP boundaries of other vectorised math routines ...
Answer to: Find the absolute maximum and absolute minimum values of f(x) = \sin x + \sqrt{3} \cos x on the closed interval [0, \sqrt{3} ]. By...
Therefore, the roots of the above equationx=1can not be accepted as we know that the maximum value of the sine function is 1 and the Sin18 Value must be less than 1. Because the roots of the sine will always lie between 1 and -1, we know that therangeof sine function is $ -1...