Simplify completely: \left( \frac{x^{ 3}y^3 z^{ 4{y^{ 3}x^5 z^{ 6 \right)^{ 1} . Simplify: (x + 9)^2 Simplify: \frac{\sqrt{280x^{6}{\sqrt{7x Simplify: 14 x^2 + 4 + 3 x - 12 x^2 - 3 + 11 x. Simplify: (v^2-36) (6 -v). ...
解析 Simplify the numerator.( ((x+1)(x-1))/(x^2-2x+1))Factor using the perfect square rule.( ((x+1)(x-1))/(((x-1))^2))Cancel the common factor of ( x-1) and ( ((x-1))^2).( (x+1)/(x-1))反馈 收藏
解析 Rewrite ( 1) as ( 1^2).( (x^2-1^2)/(x^2+1))Since both terms are perfect squares, factor using the difference of squaresformula, ( a^2-b^2=(a+b)(a-b)) where ( a=x) and ( b=1).( ((x+1)(x-1))/(x^2+1))...
x - 1 Simplify ——— x + 2 Equation at the end of step2: (x2) (x-1) 3 ((———•———)•(x+2))•—— (x+2) x+2 x3 Step3: x2Simplify ——— x + 2 Equation at the end of step3: x2(x - 1) 3 ((——— • ———) • (x + 2)) • —— x ...
கழிக்க(2x+1)(x−2)x−4-2x2−5x+2x−4 View Solution Simplifyx−3x2−x−6+2x−12x2+5x−3−2x+5x2+5x+6 View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths ...
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Multiply( ((x^2-1))^2) by ( x^2-1) by adding the exponents. ( ((x^2-1))^3) Use the Binomial Theorem. ( ((x^2))^3+3((x^2))^2⋅ -1+3x^2((-1))^2+((-1))^3) Simplify each term. ( x^6-3x^4+3x^2-1) 反馈...
The exponent in this last expression is an infinite geometric series with sum (12)(1- ( -12 ) )= (12)(32)= 13, so x^( 1/2)⋅ x^(- 1/4)⋅ x^( 1/8)⋅ x^(- 1/(16))⋅ ...=x^( 1/3)=√ [3]x.反馈 收藏 ...
View Solution What is the simplified value of (x+1x)(x2+1x2)(x4+1x4)(x8+1x6)(x16+1x16) View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
Answer to: Differentiate and simplify completely. { \frac{x^2(1-x)^3}{ (1+x)^3} } By signing up, you'll get thousands of step-by-step solutions...