Step 1: Start with the LHSWe begin with the left-hand side: LHS=tanθsecθ−1 Step 2: Substitute Trigonometric IdentitiesRecall that secθ=1cosθ and tanθ=sinθcosθ. We can rewrite the LHS as: LHS=sinθcosθ1cosθ−1 Step 3: Simplify the DenominatorThe denominator can be simpli...
If 1/(sec theta-tan theta)-1/(cos theta)= Sec theta xx k, ,0^@< theta< 90^@ then k is equal to: यदि 1/(sec theta-tan theta)-1/(cos theta)= Sec theta xx k है
用三角函数tan来表示inclination angle。在直角三角形中, \(tan(\theta) = \frac{y}{x}\)。因此:\[tan(\theta) = \frac{x^2}{x} = x\]然后我们得到:\[\theta = tan^{-1}(x)\]3. **对时间求导 根据题意, \( \frac{dx}{dt} = 5 \) units/sec。现在我们要找出 \(\frac{...
因为sec(θ)sec(θ)的导数为sec(θ)tan(θ)sec(θ)tan(θ),所以sec(θ)tan(θ)sec(θ)tan(θ)的积分为sec(θ)sec(θ)。 sec(θ)+C+∫−4eθdθsec(θ)+C+∫-4eθdθ 由于−4-4对于θθ是常数,所以将−4-4移到积分外。
sin cos 图像如下图：csc 图像如下图：sec图像如下图：tan cot图像如下图：希腊字母读音如下：1 Α α alpha a:lf 阿尔法2 Β β beta bet 贝塔3 Γ γ gamma ga:m 伽马4 Δ δ delta delt 德尔塔5 Ε ε epsilon ...
( (sec)(θ )+C-3(e^(θ )+C)) Simplify. ( (sec)(θ )-3e^(θ )+C) The answer is the antiderivative of the function( R(θ )=(sec)(θ )(tan)(θ )-3e^(θ )). ( 2(θ )=)( (sec)(θ )-3e^(θ )+C)反馈 收藏 ...
tan \theta ) ( \sec \theta - \tan \theta ) =\$ \$( \sec \theta + \tan \theta ) ( \sec \theta - \tan \theta ) =\$ \$( \sec \theta + \tan \theta ) ( \sec \theta - \tan \theta ) =\$ \$( \sec \theta + \tan \theta ) ( \sec \theta - \tan \theta...
\(\tan\theta=\dfrac{y}{x}\) 显然当\(P\)在第一象限即\(\theta\)为第一象限角时,三角函数的定义与之前相同,但是在平面直角坐标系中定义三角函数就使得其可以不受直角三角形的限制,扩展到任意象限角。 显然对于不同象限的角,\(\sin,\cos,\tan\)的值的正负是不同的: ...
Answer to: Simplify: 1) \frac{-\sin(-x) \cos x \sec x \csc x \tan x}{\cot x} \\2) \frac{1 + \tan^2 \theta}{\csc^2 \theta} + \sin^2 \theta +...
https://socratic.org/questions/how-do-you-prove-cottheta-tantheta-cscthetasectheta Please see below. Explanation:cotθ+tanθsinθcosθ+cosθsinθsinθcosθcosθ×cosθ+sinθ×sinθ... How do you prove(secθ−tanθ)(cscθ+1)=cotθ?