Two colons (::) are used in C++ as a scope resolution operator. This operator gives you more freedom in naming your variables by letting you distinguish between variables with the same name. For example, MyFile:
A scope resolution operator without a scope qualifier refers to the global namespace. C++ namespaceNamespaceA{intx; }intx;intmain(){intx;// the x in main()x =0;// The x in the global namespace::x =1;// The x in the A namespaceNamespaceA::x =2; } ...
In case it is desired to use the value of the global variable, scope resolution operator(::) has to be used before the variable. Example Illustrates the use of scope resolution operator to use the value of global variable. #include int val = 250; void main() { int val = 300; /...
问怀疑:：(scope_resolution_operator)的用法EN不，它不是。因为您执行了一个限定的名称查找。这意味着...
You might want to qualify an overloaded function name. If you do not qualify it,dbxdisplays an overload list so you can choose which function you will navigate. If you know the function class name, you can use it with the double colon scope resolution operator to qualify the name. ...
“双冒号操作符”也或称为“作用域限定操作符”(Scope Resolution Operator)可以访问静态、const和类中重写的属性与方法。在类 … www.cnblogs.com|基于33个网页 3. 范畴解析运算子 ...amesapce) std 所定义的,而 :: 为范畴解析运算子(scope resolution operator) ,接在名称空间之后,其后才是所用之名称。
Using the scope resolution operator with no name prefix The scope resolution operator can also be used in front of an identifier without providing a namespace name (e.g. ::doSomething). In such a case, the identifier (e.g. doSomething) is looked for in the global namespace. #include ...
For additional information about the :: scope resolution operator, seeObject-Oriented Programming. Example The following example creates a form and adds two command buttons to the form. By clicking either button, you can exit the form – the second button,cmdAnotherButton, calls the Click procedur...
the class access operators,.(dot), or->(arrow), or::(scope resolution) operator, you can only use a class member in a member function of its class and in nested classes. You can only use types, enumerations and static members in a nested class without qualification with the::operator....
“ENERROR in Cannot use 'in' operator to search for 'providers' in null 这个错误一直伴随着我...