由于一开始看错题目,以为rotate的部分要逆置。所以这里还是post出逆置的code。 AI检测代码解析 # Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def reverse(self, head): org_head = head cur...
node.value = i; pointer.next = node; pointer = pointer.next; }returnlist; }publicstaticvoidmain(String[] args){RotateListrotateList=newRotateList(); print(rotateList.rotate(generateList(5),5)); print(rotateList.rotate(generateList(5),2)); print(rotateList.rotate(generateList(5),0)); ...
【leetcode】61. Rotate List 题目说明 https://leetcode-cn.com/problems/rotate-list/description/ 给定一个链表,旋转链表,将链表每个节点向右移动 k 个位置,其中 k 是非负数。 解法1 解法2...Leetcode 61. Rotate List Given a linked list, rotate the list to the right by k places, where k ...
Given a list, rotate the list to the right bykplaces, wherekis non-negative. For example: Given1->2->3->4->5->NULLandk=2, return4->5->1->2->3->NULL. 前边做过一个数组的翻转。数组的翻转用一个示例解释: k=K%len(num) num=[1,2,3,4,5],k=2 第一步,翻转 num=[5,4,3,2...
[leetcode]61. Rotate List 忘记哪一题了,反正和前面有一题很像,挺简单的 Solution 1: 利用循环链表O(n) int dis=count-k%count; 利用这个式子,将问题转换为–找新的head node即可...LeetCode--61. Rotate List 题目链接:https://leetcode.com/problems/rotate-list/ 这个题目思路比较简单,但是处理...
leetcode Rotate List 1. 题目描述 Given a list, rotate the list to the right bykplaces, wherekis non-negative. For example: Given 1->2->3->4->5->NULL andk= 2, return 4->5->1->2->3->NULL....
[LeetCode] Rotate List Rotate List Given a list, rotate the list to the right by k places, where k is non-negative. For example: Given 1->2->3->4->5->NULL and k = 2, return 4->5->1->2->3->NULL. Time Complexity 计算LinkedList长度: O(N)...
Given a list, rotate the list to the right by k places, where k is non-negative. For example: Given 1->2->3->4->5->NULL and k = 2, return 4->5->1->2->3->NULL. 这题要求把链表后面k个节点轮转到链表前面。 对于这题我们首先需要遍历链表,得到链表长度n,因为k可能大于n,所以我们...
Sort a linked list in O(n log n) time using constant space complexity. Reck Zhang 2021/08/11 2010 LeetCode 61. Rotate List c++ 题目c++ /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }...
[LeetCode]--61. Rotate List 简介:Given a list, rotate the list to the right by k places, where k is non-negative.For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL Given a list, rotate the list to the right by k places, where k is non-...