在return里写条件语句 return0if ans== n+1else ans 参考 力扣:长度最小的子数组 classSolution:defminSubArrayLen(self, s: int, nums: List[int]) ->int:ifnotnums:return0 n=len(nums) ans= n + 1start, end=0, 0 total=0whileend <n: total+=nums[end]whiletotal >=s: ans= min(ans, ...
if n==k or k==0: return 1 else: return f (n1, k) +f (n1, k1) 执行语句 ans=f (5,3)后, ans的值为( ) A. 2 B. 8 C. 10 D. 20 相关知识点: 试题来源: 解析 [答案]C [解析] [详解]本题考查递归函数。这个函数的递归终止条件是 n==k 或 k == 0。 ans=f (5,3...
结果1 题目【题目】#include iostream using namespace std;int ans = 0;if (n == 1)return 1;for (i = x; i = m / n; i++)ans += g(m - i, n - 1, i);return ans;}int main(){int t, m, n;cin m n;cout g(m, n, 0) endl;return 0;}输入:8 4输出: ...
...) bool work(int x,int y,int z) { int i; if (y==9) x++,y=0; if (x==9) { ans=z; return...if (table_for_solve[x][y]) { if(work(x,y+1,z+table_for_solve[x][y]*h[x][y])) return...(true); else return(false); } else { for (i=1;i<=ss;i++) if...
intans =0;for(inti =0; i < n; ++i) {if(s[i] =='/') {intcnt1 = i ==0?0: a[i-1];intcnt2 = i == n-1?0: b[i+1];ans = max(ans,2*min(cnt1, cnt2)+1);}} cout<< ans <<endl; return0;} 暴力:#include<bits/stdc++.h>usingnamespacestd; ...
bool work(int x,int y,int z) { int i; if (y==9) x++,y=0; if (x==9) { ans=z; return(true); } if (table_for_solve[x][y]) { if(work(x,y+1,z+table_for_solve[x][y]*h[x][y])) return(true); else return(false); } else { for (i=1;i<=ss;i++) if (!
定义如下函数:def fn(x):if x<=2:return xelse:return fn(x-1)+fn(x-2)ans=fn(6)print(ans)执行上
结果1 题目 #include iostream using namespace std;int ans = 0;int i;if (n ==1)return 1;for (i = x; i = m / n; i++)ans += g(m- i, n - 1, i);return ans;}int main(){int t, m, n;cin m n;cout g(m, n, 0) endl;return 0;}输入:84输出: 相关知识点: ...
int l = ci -1; int r = ci + 1; while (ans.size() < k) { if (l == -1) { ans.add(arr[r++]); } else if (r == n) { ans.add(arr[l--]); }else{ int dis = Math.abs(arr[l] - x) - Math.abs(arr[r] - x); ans.add(dis <= 0 ? arr[l--] : arr[r++]...
ENfunc(n) ={如果n= 1，则返回a；如果n=2，则返回b；如果n=3，则返回c；如果n>3，则返回func...