2. MySQL (日期、天数)转换函数:to_days(date), from_days(days) select to_days('0000-00-00'); -- 0 select to_days('2008-08-08'); -- 733627 select from_days(0); -- '0000-00-00' select from_days(733627); -- '2008-08-08' 1. 2. 3. 4. 5. 6. 7. 8. 3. MySQL Str ...
2. MySQL (日期、天数)转换函数:to_days(date), from_days(days) select to_days('0000-00-00'); -- 0 select to_days('2008-08-08'); -- 733627 select from_days(0); -- '0000-00-00' select from_days(733627); -- '2008-08-08' 3. MySQL Str to Date (字符串转换为日期)函数:str...
一:使用 datetime 模块 from datetime import datetime # 两个日期 date1 = datetime(2023, 10, 17) date2 = datetime...(2023, 10, 10) # 计算日期差 delta = date1 - date2 # 提取天数差 days_difference = delta.days print(f"日期1与日期2相差...计算指定日期和今天的差多少天 # 给定日期字符...
If the Invoice# is the same, and the StatusCD is in both I and O then give me the date difference (in days), basically 2021-04-10 (StatusCD O) - 2021-04-01 (Status I). It will always be StatusCD O date - StatusCD I date. I would expect to see 10 days as the result. ...
delete 订单表 where datediff( dd, order_addtime, getdate() ) > 3 用函数datediff() datediff( dd, 时间1, 时间2 ),意思是:计算时间1到时间2之间的天数 所以,datediff( dd, order_addtime, getdate() ) > 3,就是超过3天的 今天 select * from 表名 where to_days(时间字段名) = to_days(now...
(2023, 10, 10) # 计算日期差 delta = date1 - date2 # 提取天数差 days_difference = delta.days print(f"日期1与日期2相差...- given_date # 提取天数差 days_difference = time_difference.days print(f"给定日期和今天相差 {days_difference} 天。...# 计算日期差 delta = date1 - date2 # ...
TIMESTAMPDIFF() Return the difference of two datetime expressions, using the units specified TO_DAYS() Return the date argument converted to days TO_SECONDS() Return the date or datetime argument converted to seconds since Year 0 UNIX_TIMESTAMP() Return a Unix timestamp UTC_DATE() Retu...
1、ADDDATE ADDDATE() 函数在指定的日期/时间上加上指定到时间间隔加并返回新的日期/时间. ADDDATE的常见语法ADDDATE(date,INTERVAL expr unit)和 ADDDATE(date,days) date:需要操作的日期。 days:在 date 上加上的天数。 value:时间/日期间隔。正数和负数都是允许的。 unit:时间/日期间隔的单位。 时间/日期...
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@days := TIMESTAMPDIFF(DAY, DATE_ADD(date1, INTERVAL @years * 12 + @months MONTH), date2), IF (@days = 1, ' day', ' days') ) ; Subject Written By Posted Difference Betweeen Two Dates And Output In Year,Month,Day war head ...