LeetCode 283 Move Zeroes Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. Example: Note: You must do this in-place witho...【LeetCode 283】Move Zeroes 题目描述: 把数组中的所有0移到数组的末尾,...
Leetcode 283:Move Zeroes Given an array nums, write a function to move all 0'sto the end of it while maintaining the relative order of the non-zero elements. 几个要点: 将 0 全部移动到数组后面 不打算非 0 元素的顺序 [法1] 暴力法 ...[...
283. Move Zeroes FindHeaderBarSize Easy Topics Companies Hint Given an integer arraynums, move all0's to the end of it while maintaining the relative order of the non-zero elements. Notethat you must do this in-place without making a copy of the array. Example 1: Input:nums = [0,1,...
leetcode 73 Set Matrix Zeroes 详细解答 解法1 此题如果空间复杂度为O(MN),则题目简单,只需要将为0的下标用一个集合保存起来,然后再判断所遍历的数字是否在集合内。 但根据题目要求,最好不要用空间复杂度为O(MN)的方法来做 解法2 只申请两个set用以保存数值为0的行列的下标,这样的空间复杂度就是O(M +...
13 14 15 16 17 18 19 classSolution { public: voidmoveZeroes(vector<int>& nums) { intcnt = 0; intidx = 0, len = nums.size(); for(inti = 0; i < len; i++) { if(nums[i] == 0) { cnt++; }else{ swap(nums[idx], nums[i]); ...
https://leetcode-cn.com/problems/move-zeroes/ 解法一 时间复杂度:O(n) 空间复杂度:O(1) 思路:将非零值覆盖数组前方,尾部赋为零值 voidmoveZeroes(vector<int>& nums){intj =0;for(inti =0; i < nums.size(); i ++) {if(nums[i] !=0) ...
class Solution{public:voidmoveZeroes(vector<int>&nums){intlen=nums.size();intj=0;for(inti=0;i<len;i++){if(nums[i]!=0){swap(nums[i],nums[j++]);}}}; leetcode-move-zeros-o-n-solution This is a O(n) loop and simply cannot be optimized further. –...
[Leetcode] Move Zeroes 移动零 Move Zeroes Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums =[0, 1, 0, 3, 12], after calling your function, nums should be[1, 3, 12,...
problem 283. Move Zeroes solution 先把非零元素移到数组前面,其余补零即可。 class Solution { public: void moveZeroes(vector<int>& nums) { int j = 0; for(int i=0; i<nums.size(); i++) { if(nums[i]!=0) nums[j++] = nums[i]; ...
LeetCode之283. Move Zeroes --- 解法一:空间换时间 我使用的办法也是类似于“扫描-拷贝”这种的,不过稍微有些不同,是使用了一个队列来记录空闲的位置信息,然后每次需要移动的时候出队列就可以了,这样可以做到最少的拷贝次数。 扫描到一个元素的时候情况可能有以下几种: nums[i]==0 --> 放入下标队列,没有...