(leetcode题解)Max Consecutive Ones Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3. Not...
题目地址:https://leetcode-cn.com/problems/max-consecutive-ones-ii/题目描述Given a binary array, find the maximum number of consecutive 1s in this array if you can flip at most one 0.Example 1:Input: [1,0,1,1,0] Output: 4 Explanation: Flip the first zero will get the the maximum ...
Max Consecutive Ones[LeetCode 485] Ans...【LeetCode】485 Max Consecutive Ones 原题地址:485. Max Consecutive Ones。 解法一 记录连续一的起始点和终点,计算最大长度。时间复杂度O(n)。 解法二 参考的更简洁的写法。时间复杂度O(n)。 参考: C++ solution with O(n)...Leetcode 485 Max Consecutive...
leetcode 485. Max Consecutive Ones Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. ......
Can you solve this real interview question? Max Consecutive Ones - Given a binary array nums, return the maximum number of consecutive 1's in the array. Example 1: Input: nums = [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last
题目地址:https://leetcode.com/problems/max-consecutive-ones-iii/ 题目描述 Given an arrayAof 0s and 1s, we may change up toKvalues from 0 to 1. Return the length of the longest (contiguous) subarray that contains only 1s. Example 1: ...
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leetcode 485. Max Consecutive Ones Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s....
0485-Max-Consecutive-Ones/cpp-0485 CMakeLists.txt main.cpp 0490-The-Maze 0494-Target-Sum 0497-Random-Point-in-Non-overlapping-Rectangles 0498-Diagonal-Traverse 0501-Find-Mode-in-Binary-Search-Tree 0509-Fibonacci-Number 0518-Coin-Change-2 0519-Random-Flip-Matrix 0528-...
3 LeetCode 485 3.1 题目 先上英文版的题目,再看中文版。 3.2 解法一:逐个元素判断 fromtypingimportListclassSolution:deffindMaxConsecutiveOnes(self,nums:List[int])->int:##注意这里是“List“,而不是”list“;ifnumsisNoneorlen(nums)==0:## 如果列表 lis 为空return0count=result=0## 计数变量,结果...