（2k+1）πi，（k=0,±1,±2···）。在实数范围内，负数是没有对数。而在复数范围内，负数是有对数的，ln(-1)=(2k+1)πi。求解过程如下：首先我们设，-1=z=x+iy，则x=-1，y=0，Φ=arg（-1）=arctg（y/x）=arctg0=π ln(-1)= ln|-1|+iArg（-1）=ln|-1|+iarg（-1...
The limit of natural logarithm of infinity, when x approaches infinity is equal to infinity: lim ln(x) = ∞,whenx→∞ Complex logarithm For complex number z: z = reiθ= x + iy The complex logarithm will be (n = ...-2,-1,0,1,2,...): ...
ln(-1)==（2k+1）πi,（k=0,±1,±2···）解题思路：设-1=z=x+iy,则x=-1,y=0 Φ=arg（-1）=arctg（y/x）=arctg0=π 则 ln(-1)= ln|-1|+iArg（-1）=ln|-1|+iarg（-1）+2kπi =0+πi+2kπi =（2k+1）πi,（k=0,±1,±2···）...
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Branded lngredient Profiles.The article presents information on several branded ingredients, including KoACT, enVantec and Magtein, and profiles several companies, including AIDP Inc., Albion and Beneo GMBH, that manufacture them.EBSCO_bspFunctional Ingredients...
解：y=ln（x）的定义域：x＞0 -1＜0，所以：ln（-1）没有意义。
ln(z)表示复数z的自然对数,其中z=x+iy,x和y分别为复数的实部和虚部。复数对数的求解相对于实数来说要复杂一些,因为它涉及到复平面的角度和幅度的计算。以下是求解复数函数ln(z)的步骤。 1. 确定复数的极坐标形式 首先,将复数z转换为极坐标形式,即z=re^(iθ),其中r是复数的模,θ是复数的辐角。模可以...
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Let f(x) = ln (x+2y-2) evaluate and simplify the expression f(e^2,1). Let f(x) = ln (x+2y-2) evaluate and simplify the expression f(1,1). Let f(x) = ln (x+2y-2) evaluate and simplify the expression f(0,1). Find the followi...
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