(1)先将指针head移动到开始逆置的节点modify_list_tail(2) 按照之前#206 Reverse Linked List的做法,将[m,n]这一段逆置(3)将被逆置的一段和逆置段前驱,逆置段后继连接起来(4)考虑特殊情况:m=1? 如果是从第一个节点开始逆置,那么最后就不需要连接pre_head了(...
Reverse a linked list from positionmton. Do it in one-pass. Note: 1 ≤m≤n≤ length of list. Example: Input: 1->2->3->4->5->NULL, m = 2, n = 4Output:1->4->3->2->5->NULL 根据经验,先建立一个虚结点dummy node,连上原链表的头结点,这样的话就算头结点变动了,我们还可以通过d...
{cout<<"node "<<count<<" - data: "<<node->data<<endl;node=node->next;count++;}}Node*reverseList(structNode*node){autohead=node;Node*n=nullptr;Node*next=nullptr;while(head){next=head->next;head->next=n;n=head;head=next;}returnn;}intmain(){structNode*tmp,*head=nullptr;vector<...
第二个是递归的终止条件if(NULL==head||NULL==head->next)returnhead;ListNode*result=reverseList(head->next);// 循环递归找到最后一个节点 (head->next为最后一节点) 那么 result指向最后节点 以【A B C D】为例 指向 Dhead->next->next=head;//以【A B C D】为例 最底部到达此处时 head 为 C...
classSolution:defreverseList(self,head:ListNode):ifhead==Noneorhead.next==None:returnhead# 递归,直到head.next == None (到了最末尾节点,返回赋值给head)newHead=self.reverseList(head.next)# 反转节点head.next.next=head head.next=NonereturnnewHead ...
原题Reverse a singly linked list. Example: Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? Reference Answer 思路分析 解题方法有很多种: 借助python list,保存每个节点,再反向...Leetcode92. Reverse Linked List II反转链表 反转从位置 m 到 n ...
Reverse Linked List/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public: ListNode* reverseList(ListNode* head) {
>>> llist = LinkedList() >>> llist None >>> first_node = Node("a") >>> llist.head = first_node >>> llist a -> None >>> second_node = Node("b") >>> third_node = Node("c") >>> first_node.next = second_node ...
代码: #include <cstdio> #include <cstring> #include <string> using namespace std; struct node { int val; int next; }; node a[100005]; int reverse(node *a, int head) { int answer = -1; while (head >= 0) { int next = a[head].next; ...
Argument 1: The head node of the list Call: SL_REVERSE(head); SL_CONCAT This function concatenates two linked lists. For example, list1: a->b and list2: c->d becomes a->b->c->d. Argument 1: The head node of the first list Argument 2: The head node of the second list Call...