L'Hopital's rule equates a limit of a quotient to the limit of the derivatives of the denominator and the numerator of the quotient to solve a limit that holds the form {eq}\displaystyle \frac{0}{0} {/eq} or {eq}\displaystyle \frac{\infty}{\inft...
L'Hopital's rule is doable if a limit produces the structure {eq}\displaystyle \frac{0}{0} {/eq} or {eq}\displaystyle \frac{\infty}{\infty} {/eq}. If the function in a limit producing either of these forms is a rational function containing po...
(split)ln y&=ln limlimits_(x→0)3x^(4x)\&=limlimits_(x→0)ln(3x)^(4x)\&=limlimits_(x→0)4xln(3x)\&=0.00(split)4limlimits_(x→0)1(1/x)ln(3x)L'H=4⋅(1/x)(-1/(x^2))=-4x ⇒ 0ln y=0y=1(Lim)=1反馈 收藏 ...
Both limits are equal to zero, L'Hopital's rule may be used limx→2ln(x−1)x−2=limx→2d(ln(x−1))dxd(x−2)dxlimx→2ln(x−1)x−2=limx→2d(ln(x−1))dxd(x−2)dx =limx→21/(x−1)1=1/(2−1)1=1=limx→21/(x−1)1=1/(2−1)1=1...
exp(sym(1)) instead of exp(1). The problem is, exp(1) is not the same as exp(sym(1)). exp(1) is internally converted to a double precision number, BEFORE it is passed to the symbolic tool. The latter is a symbolic form. The former, just a number that closely approximates t...
L’Hôpital’s rule, in analysis, procedure of differential calculus for evaluating indeterminate forms such as 0/0 and ∞/∞ when they result from an attempt to find a limit. It is named for the French mathematician Guillaume-François-Antoine, marq