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当 ni 右侧相邻兄弟节点 ni+1 存在时,先访问 ni 的子树,再访问 ni+1 。对于以 ni 为根的子树节点数 step(ni) ,可按照层次遍历计算,找到第 i 层最左侧和最右侧孩子节点 firsti 和 lasti ,通过公式 firsti = 10 × firsti − 1 和 lasti = 10 × lasti − 1 + 9...
Question难度:简单给定一个只包括 '(',')','{','}','[',']' 的字符串 s ,判断字符串...
初学者如果有 C 语言基础的话,入门 C++ 会容易很多,两种语言基础语法差别不大,类和模板才是 C 和...
// } // return count; unordered_map<int,int>mp; for(int i = 0; i<nums.size(); i++){ int diff = i-nums[i]; int good = mp[diff]; badPair += i-good; mp[diff] = good+1; } return badPair; } }; 0 comments on commit 54c0bfa Please sign in to comment. Footer...
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