如果未指定,则编译器将尝试推断其类型。 函数体(function body)指定 lambda 被调用时将执行的代码。 以下是在C++中使用 lambda 的几种不同方式: 函数回调(Function Callbacks) 默认捕获(Capturing default) 值捕获(Capturing by value) 引用捕获(Capturing by reference) 可变lambda(Mutable Lambdas) 1、函数回调 函...
publicstaticclassVariableScopeWithLambdas{publicclassVariableCaptureGame{internalAction<int>? updateCapturedLocalVariable;internalFunc<int,bool>? isEqualToCapturedLocalVariable;publicvoidRun(intinput){intj =0; updateCapturedLocalVariable = x => { j = x;boolresult = j > input; Console.WriteL...
For efficiency and correctness, you nearly always want to capture by reference when using the lambda locally. This includes when writing or calling parallel algorithms that are local because they join before returning. 为了效率和正确性,在本地使用lambda表达式时,你差不多总是需要通过引用方式捕捉变量。...
1TEST (test1, lambda_6) {2//in a class-function, lambda's capture list is this point, so could access and modify the class non-const variable3classcls {4inta;5intb;6intc;7constintd;8public:9cls():a(1), b(2), c(3), d(5) {}10~cls(){}11voidtestlambda() {12auto lambda...
std::function< size_t(const char*)> print_func; /// normal function -> std::function object size_t CPrint(const char*) { ... } print_func = CPrint; print_func("hello world"): /// functor -> std::function object class CxxPrint ...
A static lambda can't capture local variables or instance state from enclosing scopes, but can reference static members and constant definitions. C# language specification For more information, see theAnonymous function expressionssection of theC# language specification. ...
int main(){int x = 100, y = 200;auto print = [&] { // Capturing object by referencestd::cout << __PRETTY_FUNCTION__ << " : " << x << " , " << y << std::endl; }; print();return0;} 上面代码的输出如下：main()::<Lambda()> : 100 , 200 在上面的例子中，我...
Capture by reference should be preferred over capture by value whenever you would normally prefer passing an argument to a function by reference (e.g. for non-fundamental types). Here’s the above code with ammo captured by reference: #include <iostream> int main() { int ammo{ 10 }; ...
Writing [=] in a member function appears to capture by value, but actually captures data members by reference because it actually captures the invisible this pointer by value. If you meant to do that, write this explicitly. 这种做法难于理解。在成员函数中的捕捉列表[=]看起来是值捕捉,但是由于...
int a = 1; int b = 2; // capture by reference auto lambda_Add_ByRef = [&](int c, int d)->int { a = 3; b = 4; return c + d; }; std::cout << "lambda_Add_ByRef : " << lambda_Add_ByRef(1, 2) << ",a=" << a << ",b=" << b << endl; Output : lambda...