Lambda 的定义使用以下语法: [ capturelist] ( argumentlist) ->returntype {functionbody} 捕获列表(capture list)用于指定 lambda 中可访问的来自外部作用域的变量。变量可以通过值捕获、引用捕获或使用 this 捕获。 参数列表(argument list)指定将递给 lambda 的参数。 返回类型(return type)指定 lambda 将返回的...
($"Local variable before lambda invocation:{j}"); updateCapturedLocalVariable(10); Console.WriteLine($"Local variable after lambda invocation:{j}"); } }publicstaticvoidMain(){vargame =newVariableCaptureGame();intgameInput =5; game.Run(gameInput);intjTry =10;boolresult = game.isEqualTo...
For efficiency and correctness, you nearly always want to capture by reference when using the lambda locally. This includes when writing or calling parallel algorithms that are local because they join before returning. 为了效率和正确性,在本地使用lambda表达式时,你差不多总是需要通过引用方式捕捉变量。...
publicstaticclassVariableScopeWithLambdas{publicclassVariableCaptureGame{internalAction<int>? updateCapturedLocalVariable;internalFunc<int,bool>? isEqualToCapturedLocalVariable;publicvoidRun(intinput){intj =0; updateCapturedLocalVariable = x => { j = x;boolresult = j > i...
We can capture some variables by value and others by reference, but each variable can only be captured once. int health{ 33 }; int armor{ 100 }; std::vector<CEnemy> enemies{}; // Capture health and armor by value, and enemies by reference. [health, armor, &enemies](){}; // ...
[ capture list ] (parameters) -> return-type { method definition} 编译器通常会计算Lambda函数本身的返回类型。因此，我们不需要显式地给它指定一个尾置返回类型，如-> return-type。但在一些复杂的情况下，编译器无法推断返回类型，这时候我们就需要给它指定一个返回类型。为什么我们要使用Lambda函数？C++...
捕获子句(Capture Clause):这是 lambda 表达式的第一部分,您可以在其中指定预先存在的变量或定义要在表达式主体中使用的新变量。有不同的方法来指定捕获,例如: auto addTwo = [foo](){ return foo + 2; }; // by valueauto addThree = [&bar](){ return bar + 3; }; // by referenceauto addAll...
new VariableCaptureGame(); int gameInput = 5; game.Run(gameInput); int jTry = 10; bool result = game.isEqualToCapturedLocalVariable!(jTry); Console.WriteLine($"Captured local variable is equal to {jTry}: {result}"); int anotherJ = 3...
A static lambda can't capture local variables or instance state from enclosing scopes, but can reference static members and constant definitions. C# language specification For more information, see theAnonymous function expressionssection of theC# language specification. ...
A static lambda can't capture local variables or instance state from enclosing scopes, but can reference static members and constant definitions. C# language specification For more information, see theAnonymous function expressionssection of theC# language specification. ...