A simple text scanner which can parse primitive types and strings using regular expressions. A Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace. The resulting tokens may then be converted into values of different types using the various next ...
import java.util.Scanner;public class Practice07{ public static void main(String args[]) { Scanner scanner = new Scanner(System.in); int a = scanner.nextInt(); System.out.print("请输入几个数相加："); int n = scanner.nextInt(); long s = 0; Strin...
When a scanner throws an InputMismatchException, the scanner will not pass the token that caused the exception, so that it may be retrieved or skipped via some other method. Depending upon the type of delimiting pattern, empty tokens may be returned. For example, the pattern "\\s+" will...
在刚开始使用Scanner时,总是会遇到一些问题 比如:InputMismatchException——除了类型错误以外(如:应该输入整型输成字符串),还有这个错误: publicstaticvoidmain(String[] args) { Scanner s=newScanner(System.in); System.out.println("请输入:)"); String a=s.next(); System.out.println(a); System.out....
这句代码中的input为什么在同一个java源代码文本里面只能用一次?我的意思是如果下面继续需要输入的话,用Scanner input =new Scanner(System.in)就会显示错误.比如: int lisi = 80; boolean gaodi; Scanner input = new Scanner(System.in); System.out.println("请输入张三成绩:");...
1.你使用的是jdk1.4，Scanner是jdk1.5以后才有的 2.你没有导入这个类，import java.util.Scanner
For example, what good is a computer game if you can't control any of it? What we need is input, and Java has plenty of ways of accepting input. However, we'll be using a Java Scanner for this tutorial. We're also going to deal with the simplest kind, text input. This means th...
java.util.Scanner 是 Java5 的新特征,我们可以通过 Scanner 类来获取用户的输入。..."使用next()方法接收用户的输入:"); String str = scanner.next(); System.out.println("用户输入的字符串为:" + str); //关闭Scann...
Scanner input=new Scanner(System.in); System.out.print("STB的成绩是;"); int stb=input.nextInt(); System.out.print("JAVA的成绩是;"); int java=input.nextInt(); System.out.print("SQL的成绩是;"); int sql=input.nextInt(); int diffen; double avg; System.out.println("---"); Syste...
Scanner input=new Scanner(System.in); System.out.println("输入一个带有空格的串用nextLine()输入"); String str1=input.nextLine(); System.out.println(str1); System.out.println("输入一个带有空格的串用next()输入"); String str2=input.next(); ...