The function y = 2x + 1 has a graph that is a ___. A. 则还口细据别用包极通电华专加治则还口细据别用包极通电华专加治straight line with slope 2 and y-intercept 1则还口细据别用包极通电华专加治则还口细据别用包极通电华专加治 B. 白又精统白又精统parabola白又精统白又精...
A. A variable B. A constant C. A function D. A term 相关知识点: 试题来源: 解析 B。解析:在这个方程中,“2”是固定不变的数字,符合常数(constant)的定义。选项A,变量是可以变化的值,这里“2”不变。选项C,“2”不是函数。选项D,项(term)是式子中的一部分,这里单独说“2”更准确的是常数...
Solve the Initial value problem: dy / dx = e^ {x - y}, y (0) = ln 3. Find the unique solution to the initial-value problem, x^2 y'' (x) + xy' (x) - y(x) = ln x/x^2, y(1) = -1/9, ; y'(1) = .0 (a) Verify...
Answer to: The function ff(x,y)=x^3y+2x^2-1y has 1 critical point. Find it and state whether it is a local minimum, local maximum or saddle...
Suppose point A(-1,m)is on the graph of the function y=−2x.B,C,D,respectively,are point As symmertric points of x-axis,origin,y-axis.Then the area of the quadrilateral ABCD is___.双曲线y=−2x上有一点A(-1,m
A. y = 2x + 1 B. y = 3x^2 - 2x C. y = 1/x D. y = x^3 + 2 相关知识点: 试题来源: 解析 B。本题考查二次函数的定义。二次函数的一般式为 y = ax^2 + bx + c(a ≠ 0)。选项 A 是一次函数,选项 C 是反比例函数,选项 D 是三次函数,只有选项 B 符合二次函数的形式...
完全不懂了,一定要步骤.Show that the indicated functiony1(x) is a solution of the given dif-ferential equation.Use reduction of order,to find a second solutiony2(x).(a)y′′+y=0; y1=sinx(b)xy′′+y′=0; y1=lnx(c) (1−2x−x^2)y′′+2(1+x)y′−2y=0; y1=x+1...
Supports implicit multiplication, e.g. 2x or (a+b)(a-b) or 2(x-y) which equals to (a+b)*(a-b) or 2*( x-y) Lazy evaluation of function parameters (see the IF function) and support of sub-expressions. Requires minimum Java version 11. ...
Determine if the function is a solution to the given differential equation. y=x \ln x-4x+5; {y}''-\frac{1}{x}=0. Determine whether the given function is a solution to the given differential equation. y= 3 sin 2x + e^{-x} , y'' + 4y...
The inverse of the function is found as follows. $$\begin{align} 2x+1&=y\\ 2x&=y-1\\ \therefore x&=\frac{1}{2}(y-1) \end{align} $$ If we...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a question Our experts can ...