If alpha, beta are the zeros of the polynomial f(x) = x^2 – 3x + 2, then find 1/alpha + 1/beta.
Find all the zeros of the polynomial f(x)=2x^4-3x^3-3x^2+6x-2 , if two of its zeros are sqrt(2) and -sqrt(2) .
If α and β are the zeros of the quadratic polynomial f(x) = x2 − 2x + 3, find a polynomial whose roots are (i) α + 2, β + 2 (ii) ααββααββα-1α+1,β-1β+1. Solution (i) Since and are the zeros of the quadratic polynomial Product of the zeros =...
one zero of the polynomial function f(x) = x^3+x^2 - 20x is x = 0. what are the zeros of the polynomial function? What are the zeros of the quadratic function f(x) = 2x^2 + 16x - 9? What are the zeros of the quadratic function f(x) = 8x^2 - 16x -...
View Solution If the sum of the zeros of the polynomialf(x)=2x3−3kx2+4x−5is6, then the value ofkis (a)2(b)4(c)−2(d)−4 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium ...
From the polynomial f(x)=x2+px+q, we know:- The sum of the roots (zeros) α+β=−p1=−p (using Vieta's formulas).- The product of the roots αβ=q1=q. Step 2: Calculate (α+β)2Using the value of α+β:(α+β)2=(−p)2=p2Let’s denote this as γ1:γ1=p2 ...
Find the zeros of the polynomial f(x)=x^3-5x^2-16 x+80 , if its two zeros are equal in magnitude but opposite in sign.
The correct Answer is:√3, −√3, −12 | ShareSave Answer Step by step video, text & image solution for Find all zeros of the polynomial f(x)=2x^3+x^2-6x-3 , if two of its zeros are -sqrt(3) and sqrt(3) . by Maths experts to help you in doubts & scoring excellent ma...
Step by step video & image solution for If the product of zeros of the polynomial f(x)=a x^3-6x^2+11 x-6 is 4, then a= (a) 3/2 (b) -3/2 (c) 2/3 (d) -2/3 by Maths experts to help you in doubts & scoring excellent marks in Class 10 exams.Updated...
f(x)=3x4−4x3−10x2+8x+8 , if two of its zeros are √2 and −√2 . Video Solution| ShareSave Answer Step by step video & image solution for Find all the zeros of the polynomial f(x)=3x^4-4x^3-10x^2+8x+8 , if two of its zeros are sqrt(2) and -sqrt(2) . by ...