Ifsin(x+y)=log(x+y), thendydx=(a) 2 (b) -2 (c) 1 (d)−1] View Solution Ify=esinxthe value ofdydxatx=π2is , (a) 1 , (b)e, (c) 0 ,(d) not defined . View Solution tan−1(xy)−tan−1(x−yx+y)is (A)π2(B)π3(C)π4(D)π4or3π4 ...
Similar Questions If y=(sinx)^(tanx) , find frac[dy][dx] View Solution Ify=secx⋅tanxthendydx= View Solution Ify=(secx+tanx)cotxthen finddydx View Solution View Solution View Solution
Solve cos(2x) = sinx. Solve sin²(x) + tan(x) + cos²(x) = 0 for x between 0 and π. Solve \tan^2x + \tan x - 2= 0 over the interval [0, 2\pi). Solve the following for x: x (tan 47.3º - tan 17.5º) = 389 tan 17.5º. Find all sol...
Find dy / dx of sin y = x^2. Find dy / dx. y = x^3 cos x - 13 x sin x - 13 cos x Find integral_0^pi sin 3 x (cos x) dx. If y = f({2x - 1}/{x^2 + 1}) and f'(x) = sin x^2, then find dy/dx. Given y + sin (x) = x + tan (y), find dy/dx...
The given function is {eq}f \left(x \right) = f \left(x f \left( x f \left( x \right) \right) \right) {/eq} The function values are: {eq}f \left(1...Become a member and unlock all Study Answers Start today. Try it now Create an acc...
共2条回答 > 简: 复合函数公式:y=f[g(x)],其中x称为自变量,u为中间变量,y为因变量(即函数)。设函数y=f(u)的定义域为Du,值域为Mu,函数u=g(x)的定义域为Dx,值域为Mx,如果Mx∩Du≠Ø,那么对于Mx∩Du内的任意一个x经过u;有唯一确定的y值与之对应,则变量x与y之间通过变量u形成的一种函数关系...
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Evaluate the following limit: \lim\limits_{x \to 1} \frac {x^2+3x-4}{x^2-6x+5} Evaluate the following limit. \lim_{x \rightarrow 2} \frac {2 - \sqrt{x + 2{\sqrt[3]{2} - \sqrt[3]{4 - x Evaluate the following limit. lim_{y \rightarrow 3} ...
【题目】下列各组函数能够成复合函数f()的是() A、 y=f(t)=ln(10) u=if(x)=sinx-1 C、 y=f(n)=1/(u-u^2) 与 u=in(x)=sin^3x+cos^2x-1 D、 y=f(u)=arccosu与u=(r)=3+r2 相关知识点: 试题来源: 解析 【解析】 ∵sinx-10 , ∴ln(sinx-1) 没有意义, ∴A ...
高中数学>指数函数的解析式及定义（定义域、值域）考试题目