1 if(isset($_POST['submit'])) not working 1 if(isset($_POST['submit'])) always return false 4 if(isset($_POST['Submit'])){ Not working 1 Isset($_POST['submit) is not working 0 if(isset($_POST['Submit'])){} Not working 3 isset($_POST['submit']) always false 1...
相比之下,`if(isset($_POST['submit']))` 使用`isset()`函数来检查`'submit'`键是否存在`$_POST`数组中。`isset()`是一个内置的PHP函数,它的作用是检测变量是否已设置且非NULL。如果`'submit'`键存在于`$_POST`数组中,`isset()`会返回`true`,否则返回`false`。使用`isset()`可以避免因尝试访问未定...
个人认为if(isset($_POST['submit']))效率高 $_POST['submit']是为了检验submit按钮有没有提交,也即是是初次打开表单(还没填写数据没提交),还是打开表单填写数据提交后 isset是为了验证$_POST['submit']是否初始化变量,在PHP环境一些设置警报类型中,如果没有isset检测会警报的 如果不加的话,环境编译页面时,就...
} 提交表单时 if($_POST[submit])与 if(isset($_POST[submit]))的区别 第一种方法会出现一个warning,第二种相对更严谨。 还有就是POST的键名最好加上单引号,这样效率稍微高点(大概3-4倍)。 恩 差不多那个意思,如果设置了这个变量则返回true PHP中if(isset($_POST['Submit']))是什么意思 isset -- 检...
type="submit" value="Submit" name="delete" /> and check if(isset($_POST['delete'])) then it works in this code you didn't give any name to submit button and checking its exist or not with isset(); function so php didn't find any variable like "submit" so its not ...
isset（）//判断是否设定了某个变量 _POST["submit"]//通过POST提交的变量 判断是否存在通过post方式提交过来的变量
一个if的语句.当我用 if($_POST['submit']) 写的时候,会出现warning.当我用if(isset($_POST['submit'])) 写的是时候,是正确的.而isset具体在这里使用是什么意思呢.查阅PHP手册的时候 有一段警告使用 isset() 只能用于变量,因为传递任何其它参数都将造成解析错误.若想检测常量是否已设置,可使用 defined()...
if(isset($_POST['submit'])){extract($_POST);if(array_filter($moods) && is_array($moods)){foreach($moods as $column => $value){ if(in_array($value, array('happy','bored'))){$sql = "UPDATE `tmp` SET {$column}_count = {$column}_count+1 WHERE `{$column}` = ?";...
if (isset($_POST['submit'])){ $Project_Service_Name = $_POST['Project_Service_Name']; $Project_Desc = $_POST['Project_Desc']; $sql = "INSERT INTO mrc_projectmaster (Project_Service_Name, Project_Desc) VALUES ('$Project_Service_Name','$Project_Desc')"; $result = mysql_query($...
if (isset($_POST['submit'])){ $Project_Service_Name = $_POST['Project_Service_Name']; $Project_Desc = $_POST['Project_Desc']; $sql = "INSERT INTO mrc_projectmaster (Project_Service_Name, Project_Desc) VALUES ('$Project_Service_Name','$Project_Desc')"; $result = mysql_query($...