If you combine 141.959g (or 1 moles) of Na2HPO4 (molar mass = 141.959 g/mol), 2352.174g (or 12 moles) of (NH4)2MoO4 (molar mass = 196.015 g/mol) and 1449.295g (or 23 moles) of HNO3 (molar mass = 63.013 g/mol) it will have ...
复合系数摩尔质量摩尔(克/摩尔)重量(克) 反应物 磷酸一氢钠 正钼酸铵 硝酸 Na2HPO4 1 141.95884056 (NH4)2MoO4 12 196.01452 HNO3 23 63.01284 产品 磷钼酸铵 硝酸鈉 硝酸铵 水 (NH4)3(PMo12O40) 1 1876.345142 NaNO3 2 84.99466928 NH4NO3 21 80....
(NH4)3(P(Mo3O10)4) 1 1876.345142 NH4NO3 21 80.04336 NaNO3 2 84.99466928 H2O 14 18.01528 平衡方程式 计算极限试剂 这个计算器将进行化学计量计算。 🛠️ 计算反应化学计量 ➜ Instructions To perform a stoichiometric calculation, enter...
PH3 + NaMnO4 = MnO2 + Na3PO4 + Na2HPO4 + H2O Na3PO4 + NaCl = Na3PO4 + NaCl ZnCl2 + HCl = ZnCl2 + HCl Fe + I2 = Fe3I2 C6H5CH2OH + CuO = Cu + H2O + C6H5CHO 近期平衡的方程式 練習 FePO4-++(NH4)2MoO4-++HNO3-...
aNa2HPO4+bHNO3=cNaNO3+dNaH2PO4 Step 2: Create a System of Equations Create an equation for each element (Na, H, P, O, N) where each term represents the number of atoms of the element in each reactant or product. Na:2a +0b=1c +1dH:1a +1b =0c+2dP:1a +0b=0c+1dO:4...
复合系数摩尔质量摩尔(克/摩尔)重量(克) 反应物 磷酸一氢钠 正钼酸铵 硝酸 Na2HPO4 1 141.95884056 (NH4)2MoO4 12 196.01452 HNO3 23 63.01284 产品 磷钼酸铵 硝酸铵 硝酸鈉 水 (NH4)3(PMo12O40) 1 1876.345142 NH4NO3 21 80.04336 NaNO3 2 84.9...
(NH4)2MoO412196.01452 产品 磷钼酸铵硝酸铵水硝酸鈉 (NH4)3PO4·12MoO311876.345142 NH4NO32180.04336 H2O1218.01528 NaNO3284.99466928 这个计算器将确定反应的限制试剂。 Instructions To calculate the limiting reagent, enter an equation of a chemical reaction...
The stoichiometric mole ratio of Na2HPO4*2H2O, (NH4)2MoO4 and HNO3 for a maximum theoretical yield is 1:12:23, which will yield (NH4)3(P(Mo3O10)4), NH4NO3, NaNO3 and H2O in a ratio of 1:12:23:1. If you combine177.989g ...
反应物 Dibasic Dihydratesodium Phosphate 正钼酸铵 硝酸 Na2HPO4·2H2O 1 177.98940056 (NH4)2MoO4 12 196.01452 HNO3 23 63.01284 产品 磷钼酸铵 硝酸铵 硝酸鈉 水 (NH4)3(P(Mo3O10)4) 1 1876.345142 NH4NO3 21 80.04336 NaNO3 2 84.994669...
Na2HPO4 + (NH4)2MoO4 + HNO3 = (NH4)3(PMo12O40) + NH4NO3 + NaNO3 + H2O - 计算你的化学反应和方程的化学计量。