HCF of two numbers is a factor of each of the numbers. HCF of two numbers is always less than or equal to each of the numbers. HCF of two prime numbers is 1 always. HCF of two numbers can also be found out with help of the listing factors method. In this method, we list out a...
The Highest Common Factor (HCF) of two numbers is the highest possible number that divides both the numbers completely. The Highest Common Factor (HCF) is also called the Greatest Common Divisor (GCD).There are many ways to find the HCF of two numbers. One of the quickest ways to find ...
To determine whether the statement "HCF of two numbers is always a factor of their LCM" is true or false, we can analyze the relationship between HCF (Highest Common Factor) and LCM (Lowest Common Multiple) using mathematical definitions and examples.
百度试题 结果1 题目The HCF of two natural numbers is 12 while the LCM is 120. If one of the number is 24, find the other number. 相关知识点: 试题来源: 解析 60 (a,b)×[a,b]=a×b,所以12×120÷24=60.反馈 收藏
RS AGGARWAL-REAL NUMBERS-Exercise 1B Using prime factorisation, find the HCF and LCM of : , (i) 36, 84 (ii... 12:53 Using prime factorisation, find the HCF and LCM of : , (i) 8,9,25 ... 06:36 The HCF of two numbers is 23 and their LCM is 1449. If one of the numb....
The source code to calculate the HCF of two numbers is given below. The given program is compiled and executed successfully.// Java program to calculate the // HCF of two numbers import java.util.Scanner; public class Main { static int CalHcf(int num1, int num2) { int temp = 0; ...
英文: Using the Euclidean algorithm, we can quickly find the HCF of two numbers. 英文同义表达: Greatest Common Divisor (GCD):这是HCF在数学中的另一种常见表达,两者意思完全相同,都指两个或多个整数的最大正整数因数。 解释: GCD 是从“divisor”(除数)的角度出发,强调...
解析 【解析】(1)Solutions:The HCF of two consecutive numbers is 1Example: The HCF of 2 and 3 is 1(2)The HCF of two consecutive even numbers is2Example: The HCF of 2 and 4 is 2(3)The HCF of two consecutive odd numbers is1Example: The HCF of 3 and 5 is 1 ...
number is 8 more than the othernumber,then the sum of the two numbers is(A)48(B)40(C)36(D)24(E)1814.The product of the HCF and LCM of two numbers is 384.If one number is 8 more than the other number,then the sum of the two numbers is (A)48 (B)40 (C)36 (D)24 (E...
if it is, exist the functionreturnERROR;inti;intmax=(a>b)?a:b;//get the Maximum number of the two numbersfor(i=max;;i++){if(i%a==0&&i%b==0)break;}returni;//i is the HCF}intmain(){inta,b;cin>>a>>b;//input two nubersintcom=gcd(a,b);//get GCD and keep it by ...