golang如何获取map所有key的⽅式最佳⽅式:根据map的长度,新建⼀个数组,遍历map逐个压⼊ ⽅法1(效率很⾼):func getKeys1(m map[int]int) []int { // 数组默认长度为map长度,后⾯append时,不需要重新申请内存和拷贝,效率很⾼ j := 0 keys := make([]int, len(m))for k := range...
func (m *Map) Delete(key interface{}) func (m *Map) Load(key interface{}) (value interface{}, ok bool) func (m *Map) LoadAndDelete(key interface{}) (value interface{}, loaded bool) func (m *Map) LoadOrStore(key, value interface{}) (actual interface{}, loaded bool) func (m ...
func getKeys2(m map[int]int) []int { // 数组默认长度为map长度,后面append时,不需要重新申请内存和拷贝,效率很高 keys := make([]int, 0, len(m)) for k := range m { keys = append(keys, k) } return keys } 1. 2. 3. 4. 5. 6. 7. 8. 其他方式: 方法3(效率较低): func ge...
func getKeys2(m map[int]int) []int { // 数组默认长度为map长度,后面append时,不需要重新申请内存和拷贝,效率很高 keys := make([]int, 0, len(m)) for k := range m { keys = append(keys, k) } return keys } 其他方式: 方法3(效率较低): func getKeys3(m map[int]int) []int { ...