5. Factorise:(a) x^3+1/(x^3) (b) a^3-1/(b^3) () (a^3)/(27)+(b^3)/(64) (d) (x^3)/(27)-(125)/(y^3) () (27x^3)/(64)+1 相关知识点: 试题来源: 解析 c)( (C (a/3+a/4)((a^2)/9-(ab)/(12)+(b^2)/(16)) e) (-(3x)/4+1...
View Solution Factorise :x2−2x+34 View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep, NEET preparation and CBSE, UP Board, Bihar Board, Rajasthan Board...
Factorise: (1) 2x^2-x-6 (2)a^3-0.216 (3) (x^2-3x)^2-8(x^2-3x)-20 04:06 Factorize : (i)x^3+3x^2+3x-7 (ii)x^3-3x^2+3x+7 (iii) x^6-7x^3-8 08:17 Factorise: (1)2x^(2)-x-6=0(2)a^(3)-0.216 (3) (x^(2)-3x)^(2)-8(x^(2)-3x... 04:06 ((1...
3x−9+4x−4x−1×(x−3)=15x+33x−9+4x−4x−1×(x−3)=15x+37x−13x−1×(x−3)=15x+37x−13x−1×(x−3)=15x+3a7x−13x+3=15x−1x−3a7x−13x+3=15x−1x−3 7x2−13x+21x−39=15x2−60x+457x2−13x+21x−39=15x2−60...
(i) Factorise x3+8.(ii) A pyramid has a base are a of (x3+8) cm2 and volume(x^3+1/3x^2+(14)/3x+4)cm^3 .3 3(a) Show that the height of the pyramid can be expressed as A+(x^2+Bx+C)/(x^3+8) , where A, B and C are constants.x2+8)(b) Using your res...
【题目】Factorise, as far as possible, th e following expressions.$$ x ^ { 3 } + 1 g i v e n t h a t ( x + 1 ) i s a f a c t o r . $$ 相关知识点: 试题来源: 解析 【解析】 $$ ( x + 1 ) ( x ^ { 2 } - x + 1 ) $$ ...
1use the factor therem to factorise the following cubics as far as possible:f(x)=x(的三次方)-7x+62find a given that (x+4) is a factor of f(x)=x(的三次方)+8x^+ax+12 and hence factorise f(x) completely.3show that (x-2) is a factor of f(x)=x的三次方-4x^+x+6 and ...
Factorise: 3x2−4x−4 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium NCERT Solutions for Class 9 English Medium ...
If x+1 is a factor of ax^(3)+x^(2)-2x+4a-9, then value of a . 01:58 Factorise (i) x^(2)+9x+18 (ii) 6x^(2)+7x-3 (iii) 2x^(2)-7x-15 (... 05:20 Factorise (i) 2x^(3)-3x^(2)-17x+30 (ii) x^(3) -6x^(2)+11x-6 (iii... 20:06 Using suitable identit...
(1)Solution:x2 + xy + 8x + 8y = x × x + x × y + 8 × x + 8 × y=x(x + y) + 8(x + y)=(x + y)(x + 8) (2)15xy - 6x +5y - 2 = 3×5×x×y-3×2×x×5xy-2= 3x (5y - 2) +1(5y - 2)= (5y - 2) (3x +1) (3)ax + bx- ...