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Factorise 32a^(4) - 8a^(2) 01:18 Factorise 2(ab + cd) - a^(2) - b^(2) +c^(2) +d^(2) 02:55 Factorise (1-a^(2))(1-b^(2)) + 4ab 03:18 Factorise (x^(2) +y^(2) -z^(2))^(2) - 4x^(2) y^(2) 01:32 Factorise 8( 3x - 2y ) ^(2) - 6x + 4y -...
结果1 题目5 Factorise completely.x^2-6x 3x(3x-2)Answer...。[2] 相关知识点: 试题来源: 解析 3x(3x-2)final answerB1 for x(9x-6) or 3(3x²-2x) 反馈 收藏
=(x + y)(x + 8) (2)15xy - 6x +5y - 2 = 3×5×x×y-3×2×x×5xy-2= 3x (5y - 2) +1(5y - 2)= (5y - 2) (3x +1) (3)ax + bx- ay - by = a × x + b × x - a × y - b × y=x(a + b) - y(a + b)= (a + b)(x - y) ...
Factorise. x^{2}-4x-5 Factorise: (a) 4x^2-7x+3 (b) 6x^2+10x-5 Factorise: x^2 - 4x - 21. Factorise: x^2 - 14x + 49. Factorise : (1+ \frac{y^2+z^2-x^2}{2yz} ) / (1 - \frac{x^2+y^2-z^2}{2xy} ) ...
(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2a2−b2=(a+b)(a−b) Answer and Explanation:1 We have to Factorise:25x2−9. We will apply the algebraic identities to factorize the given expression: $$\begin{align} 25x^2 - 9... ...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
(1) x3−6x2+11x−6= (2) x3+2x2−x−2= (3) x3+7x2+14x+8= (4) x3−3x2−10x+24= (5) x3+2x2−13x+10= 相关知识点: 试题来源: 解析 (1) (x−1)(x−2)(x−3) (2) (x+1)(x+2)(x−1) (3) (x+1)(x+2)(x+4) (4) (x+3)(x−2)(x−4...
百度试题 结果1 题目(a) Completely factorise x^3-5x^2+6x 相关知识点: 试题来源: 解析 (a)factor of xAttempt to factorise -5x+6 or orig.cubicx(x-3)(x-2) 反馈 收藏
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...