4 (a)Multiply out.5(2x+3)(a)10x+15 final answer(b)Factorise completely.3x^2-12x(b) 3x(x- 4) final answer 相关知识点: 试题来源: 解析 10x+15 final answer3x(x- 4) final answer(b)M1 for 3(x²-4x) or x(3x-12)Condone omission of final bracket(3x+0)(×-4) or -3x(4 ...
百度试题 结果1 题目(b) Factorise fully 6x^3-27x^2+30x=3x(2x2-9x+10) [M1]=3x(2x-5)(x-2) 相关知识点: 试题来源: 解析 =3x(2x²-9x+10) [M1] = 3x(2x-5)(x-2) 反馈 收藏
(ii) Factorise 2x^4+5x^3-8x^2-8x+3 completely. 相关知识点: 试题来源: 解析 http://gallery.fbcontent.cn/latex?decode=false&latex=%24%24%5Cleft(x%5E%7B2%7D%2B3%20x-1%5Cright)(2%20x-3)(x%2B1)%24%24%25&fontSize=28 反馈 收藏 ...
10 Factorise the following expressions completely.(a) 3mn+mn2(b)3x(2x-y)+6y(y-2x) 相关知识点: 试题来源: 解析 10(a)3mn+mn²=mn(3+n)10(b)3x(2x-y)+6y(y-2x)= 3x(2x-y) - 6y(2x -y)= (3x- 6y)(2x -y)= 3(x- 2y)(2x-y) ...
1a level的数学.1.Simplify (x^3+7^x2+5x-28)/(x+4)2.Factorise completely x^3+5x^2-2x-243.Make r the subject of the formula 4.If ,find the value of y when x = 9 given that y = 24 when x = 4 .5.The probability that I oversleep on any given day is 1/10.If I ...
(1) x4−1= (2) 32x8−162= (3) 50(2x+1)2−18(1−x)2= 相关知识点: 试题来源: 解析 (1) (x2+1)(x+1)(x−1) (2) 2(4x4+9)(2x2+3)(2x2−3) (3) 2(7x+8)(13x+2) (1)N/A.(2)N/A.(3)N/A.反馈
百度试题 结果1 题目Factorise fully(x+3)^7+(x+3)^6(2x-1)Do not attempt to expand brackets. 相关知识点: 试题来源: 解析 (x+3)^6[(x+3)+(2x-1)] (x+3)^6(3x+2) 反馈 收藏
Factorise: $2x^3-5x^2-19x+42$ 相关知识点: 试题来源: 解析 $(x-2)(2x-7)(x+3)$2n2 4w n/-|||--2-|||-(--2)-|||-(-|||-Cn-|||-2)n-|||-(n-|||-2)(pniton-n-|||-)-|||-pn+书-|||-7(-|||-(h~(7dh+) ...
factorise : 8- 4a -2 a^3 + a^4 01:02 Factorise : x^3+3xy^2-2x^2y-6y^3 00:55 Factorise : px-5q-5x+pq 00:52 Factorise : x^2+y-xy-x 00:56 factorize (a) (3a-1)^2 - 6a + 2 01:47 Factorise : (2x-3)^2-8x+12 01:05 Factorise : a^3+a-3a^2 -3 00:49 3a...
解析 (x+3)^6[(x+3)+(2x-1)] (x+3)^6(3x+2) 结果一 题目 Factorise fully(x+3)^7+(x+3)^6(2x-1)Do not attempt to expand brackets. 答案 (x+3)^6[(x+3)+(2x-1)] (x+3)^6(3x+2)相关推荐 1Factorise fully(x+3)^7+(x+3)^6(2x-1)Do not attempt to expand bracke...