We know that a^3+b^3+c^3−3abc=(a+b+c)(a^2+b^2+c^2−ab−bc−ca) i.e. , =>(a+b)^3+(b+c)^3+(c+a)^3−3(a+b)(b+c)(c+a)=((a+b)+(b+c)+(c+a))[(a+b)^2+(b+c)^2+(c+a)^2−(a+b)(b+c)−(b+c)(c+a)−(c+a)(a+b)] =>(a...
Factorise : 3a^(2) b - 12 a^(2) - 9b + 36 01:15 Factorise : x^(2) - (a - 3) x -3a 01:11 Factorise : x^(2) - (b -2) x-2b 01:07 Factorise : a(b-c) - d (c -b) 01:21 Factorise : ab^2 - (a-c) b-c 01:09 Factorise : (a^2 - b^2) c + (b^2 ...
5. Factorise:(a) x^3+1/(x^3) (b) a^3-1/(b^3) () (a^3)/(27)+(b^3)/(64) (d) (x^3)/(27)-(125)/(y^3) () (27x^3)/(64)+1 相关知识点: 试题来源: 解析 c)( (C (a/3+a/4)((a^2)/9-(ab)/(12)+(b^2)/(16)) e) (-(3x)/4+1...
百度试题 结果1 题目Fully factorise (vmatrix) a&1&a^3 b&1&b^3 c&1&c^3(vmatrix) 相关知识点: 试题来源: 解析 -(a-b)(b-c)(c-a)(a+b+c) 反馈 收藏
Answer to: Factorise: (a) 4x^2-7x+3 (b) 6x^2+10x-5 By signing up, you'll get thousands of step-by-step solutions to your homework questions. You...
Factorise a^3-b^3+1+3ab 03:26 If a + b + c = 0, then prove that 1/(2a^2+bc)+1/(2b^2+ca)+1/(2c^2+a... 05:09 If a^2 + b^2 + c^2 -ab-bc-ca = 0, then prove that a=b=c 04:14 If a + b + c = 0, then prove that (a+b)^2/(ab) + (b+c)^2...
Thus, the factorised form of the expression1−2a−2b−3(a+b)2is: (1−3(a+b))(a+b+1) --- Show More | ShareSave Class 9MATHSPOLYNOMIALS Topper's Solved these Questions FACTORISATIONBook:ICSEChapter:FACTORISATIONExercise:Exercise 5 (C) ...
1. (a) Factorise 3(3-2a)^2-2a+3-10 .(b) E*prcss(8x-5)/(2x-3)inthetomofa+b/(2x-3)wherec and bare constants.2x-32x-3(c) Givcntan2(p+q)=1/2(5p-2q) , find the value of L.(d)Solve5/(1-x)-3/(x+1)=2/(x^2-1) ...
5 (a) Factorise 5a-3a2a(5-3a)2)(b)Expand(i)2(4-3w)8-6w(ii) 1^2(y+10)+10g(3)(e) W=(5.6
Factorise each of the following quadratic expressions completely.(a) 4x^2-16(b) 75-12p^2(c) 2x^2+10x+12(d) 3x(2x-11)+15 相关知识点: 试题来源: 解析(a)4x2-16=4(x2-4) 1,4 =u(x^2-2^2) 4 and 16=4 4c2(2) Pifference between 2 squares (b) 72-12P^2=3125-4P^2 =3[...