Factorise each of the following : (i) 8a^3+b^3+12a^2b+6ab^2 (ii) 8a^3-b^3-12a^2b+6ab^2 (iii) 27-125a^3-135a+225a^2 (iv) 64a^3-27b^3-144a^2b+108ab^2
According to the splitting the middle method, we have to find two numbers d and e such that these two numbers satisfy these two conditions b=d+e and ac=de Answer and Explanation: We have to factorise: 15y4−35y3+10y2. $$\begin{align} 15y^4 - 35y^3 + 10y^2 &=5x^2(3x^...
II. Questions that require solutions1Facto rise:9a^2-6ab+3a12 Factorise_i-8x^4y+6x^3y^2-2x^3y13 FactOrise:8a^mb^3-12a^(m+1)b^2+16a^(m+2)b.14 Given that x+y= 5 and xy = 2, find the value of x5y4+x4y5. 相关知识点: 试题来源: 解析 3a(3a-2b+1)1 2-2x^3y(4x...
ਹੇਠ ਲਿਖੇ ਦਾ ਗੁਣਨਖੰਡੀਕਰਣ ਕਰੋ:-8a3−b3−12a2b+6ab2 View Solution Factorise of the following. :8a3+b3+12a2b2+6ab2. View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6...
Factorise each of the following (i) 8a ^(3) + b^(3) + 12a ^(2)b + 6ab ^(2) (ii) 8a ^(3) - b ^(3) -12a ^(2) b+ 6ab ^(2) (iii) 1- 64 a ^(3) -12a + 48 a ^(