(a) Factorise :x2−(z−5)x−5z (b) Factorise :x2+x−y+y2−2xy View Solution Factorise:(x2−5x)(x2−5x−20)+84 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium ...
解析 (x+3)^6[(x+3)+(2x-1)] (x+3)^6(3x+2) 结果一 题目 Factorise fully(x+3)^7+(x+3)^6(2x-1)Do not attempt to expand brackets. 答案 (x+3)^6[(x+3)+(2x-1)] (x+3)^6(3x+2)相关推荐 1Factorise fully(x+3)^7+(x+3)^6(2x-1)Do not attempt to expand bracke...
(1) x3−6x2+11x−6= (2) x3+2x2−x−2= (3) x3+7x2+14x+8= (4) x3−3x2−10x+24= (5) x3+2x2−13x+10= 相关知识点: 试题来源: 解析 (1) (x−1)(x−2)(x−3) (2) (x+1)(x+2)(x−1) (3) (x+1)(x+2)(x+4) (4) (x+3)(x−2)(x−4...
百度试题 结果1 题目Factorise fully(x+3)^7+(x+3)^6(2x-1)Do not attempt to expand brackets. 相关知识点: 试题来源: 解析 (x+3)^6[(x+3)+(2x-1)] (x+3)^6(3x+2) 反馈 收藏
一II. Fill in the blanks Factorise: x^2+x+1/4=4 H5:Facotise:1/4x^2-x+1= 6 Factorise: 4x^2-4x+1=7 Factorise: x^2y^2-4xy+4=8 actorise:9-12t+4t^2=9 Factorise: ()^2+20xy+25y^2=().10 Factorise:+4mm+1=()2. 相关知识点: 试题来源: 解析 , (2/I+x) ...
百度试题 结果1 题目Hence, factorise fully x^3-6x^2-x+6 相关知识点: 试题来源: 解析 =(x-1)(x²-5x-6)=(x-1)(x+1)(x-6) 反馈 收藏
root(3)x^2+11x+6root(3) ={x+[9/root(3)]}{x+[2/root(3)]} Suggest Corrections 1 Similar questions Q. Factorise √3x2+11x+6√3. Q. Factorise: x3−6x2+11x−6 Q. Factorise : x3+6x2+11x+6 Q. Factorise the expression x3−6x2+11x−6. Q. Factorise: ...
x2+11x+30. 因式分解x2+11x+30.相关知识点: 试题来源: 解析 (x+5)(x+6). x2+11x+30=(x+5)(x+6).结果一 题目 Factorise x2+11x+30.因式分解x2+11x+30. 答案 (x+5)(x+6).相关推荐 1Factorise x2+11x+30.因式分解x2+11x+30. ...
II. Fill in the blanks4Faco rise:x^2+x+1/4=5Facois: 1/4x^2-x+1=6 Factorise: 4x^2-4x+1=7Factorise: x2y2-4xy+4=8Factorise: 9-12t+4t2=Factorise:()^2+20xy+25y^2=()^2 10 Factoriset_: 相关知识点: 试题来源: 解析 (ζ/(I)+x) )(1/2x-1)^2 26 (2x-1...
(– 2) is a factor of the expression3+2+ + 6. When this expression is divided by ( – 3) it leaves the remainder 3. Find the values of & . Q. The expression4x3−bx2+x−cleaves remainders 0 and 30 when divided by x+1 and 2x-3 respectively. Calculate the values of b and...