"illegal start of expression" 是一个在Java(以及其他一些编程语言中)常见的编译错误,它表明在代码中的某个位置,编译器遇到了它无法识别或预期之外的语法元素,从而导致无法正确解析接下来的表达式。这通常是因为在表达式开始的地方出现了非法的字符、缺少必要的符号(如分号、括号等),或者代码结构错误。 2. 列举可能...
$ javac AccessModifierInMethod.java AccessModifierInMethod.java:5: error: illegal start of expression private int sum = x + y; ^ 1 errorCopy Removing the private access modifier easily solves the problem: package com.baeldung; public class AccessModifierInMethod { public void printSum(int x,...
else monthlySalary = 0.00;改成 else monthlySalary = 0.00;
Main.java:7: error: illegal start of expression public static int count() { ^ Main.java:7: error: ';' expected public static int count() { ^ Main.java:7: error: ';' expected public static int count() { ^ Main.java:11: error: reached end of file while parsing } ^ 5 errors ...
MyClass.java:4: error: illegal start of expression public static int count() ^ MyClass.java:4: error: illegal start of expression public static int count() ^ MyClass.java:4: error: ‘;’ expected public static int count() ^ MyClass.java:4: error: ‘;’ expected ...
sample.java:4: error: illegal start of expression private int sum = x+y; 1 error You can fix this error by removing the privateaccess modifierfrom "private int sum". Char or String Without Quotes In Java, char is a primitive data type, and String is a class representing a sequence of...
语法错误、检查一下分号有没有写成冒号。
从代码看，a是字符串类型。那么a其中的每一个字符如a[i]应是char类型的，而不是字符串类型。这是容易混淆的。str()过程只能将数字转换为字符串类型，而不是字符(char)类型。
Illegal start of simple expression Lists.scala /progfun-example/src/main/scala/example line 28 Scala Problem. I'm just starting any help is appriciated.
百度试题 结果1 题目error C2052: 'type' : illegal type for case expression 中文对照:(编译错误)case表达式类型非法相关知识点: 试题来源: 解析 分析:case表达式必须是一个整型常量(包括字符型) 反馈 收藏