【题目】(a) Find an equation of the normal line to theelipse (x^2)/(32)+(y^^2)/8=1 at the point2. (b Use agraphing utility to graph the ellipse and the normal line. (c) At what other point does the normal line intersect the ellipse?
Find an equation of the normal line to the curve {eq}y = \sqrt{x} {/eq} that is parallel to the line {eq}4x + y = 1 {/eq}. Equation of the Normal Line to a Curve: A line {eq}L_{1} {/eq} is said to be normal to a curve at the p...
结果1 题目 Find the equation of the tangent line and the equation of the normal line drawn to the curve x^( 2/3)+y^( 2/3)=5 at the point (8,1). 相关知识点: 试题来源: 解析 y-1=-12(x-8)y-1=2(x-8) 反馈 收藏 ...
In the problem, we need to find the equation of the normal line to the curve of {eq}\displaystyle y= x\ln x \ at\ x= 1.65 {/eq} So we will first... See full answer below.Become a member and unlock all Study Answers Start today. Try it now Create an a...
Find the equation of the normal line to the indicated curve at the given point. x2 - y2 = 40 at (7,3) Select one: A. 3x + 7y + 42 = 0 B. 3x - 7y + 42 = 0 C. 3x - 77 - 42 = 0 D. 3x + 7y - 42 = 0 Bundohu tha...
- 5/4 Coordinates of tangent point are (1/2,-5/4)Let the equation of normal line be y = -x + c2 (3)Sub x = 1/2 and y = -5/4 into (3),we have c2 = 1/2 - 5/4 = -1/4 Sub c2 = -1/4 back into (3),finally,the normal equation is y = -x - 1/4 (Ans)
Learn how to find a normal line equation. Use a derivative and perpendicular slope of a tangent line to calculate the equation of the normal line...
find the equation of the normal to the curve y=3x2-2x-1which is perpendicular to the line y=x-3Solution:y = 3x^2 - 2x - 1 (1) Its derivative is dy/dx = 6x - 2Let the equation of tangent line be y = mx + c1 = x + c1 (2)(Tangent line is parallel to y = x - 3,...
Calculate the equation of the normal on the graph of f in point Awith x-coordinate 9是让求当x=9时的函数值吗?)2.Given is the function f(x) =22x-1 Df = [-1,2]a.Draw the graph of fThe mirror of the graph of f in the y-axis is the graph of a function g....
Find the equation of the line normal to the curve y=8−x3 at the point (−1,9). Normal Line to the Curve: The slope of the normal line to a curve at one point is the opposite of the inverse of the slope of the tangent line because they are lines perpendicular to each other...