2k² + 3k + 6 - k² - 4k - 8 = 3k² + 4k + 4 - 2k² - 3k - 6k² - k - 2 = k² + k - 2-k = k2k = 0k = 0Therefore, k is 0.✦ Try This: Determine k so that k²+ 2k + 6, 4k² + 5k + 6, 2k² +...
So, we can write:(2k2+3k+6)−(k2+4k+8)=(3k2+4k+4)−(2k2+3k+6) Step 2: Simplify the left sideCalculating the left side:(2k2+3k+6)−(k2+4k+8)=2k2+3k+6−k2−4k−8Combine like terms:(2k2−k2)+(3k−4k)+(6−8)=k2−k−2 Step 3: Simplify the right...
1. \sum_{k = 1}^\infty \frac{(-1)^{k +1} l^k}{(k +2)!}\\2.\sum_{ k = 1}^\infty \frac{\sin{ \frac{k\pi}{2}{k^4}\\3.\sum_{k = 1}^\infty (2 - \sqrtk{k})^{3k} Determine whether the following series converge or diverge: 1.\sum_{n=...
1. \sum_{k=3}^{\infty }\left ( \frac{2k-1}{3k+2} \right )^{k} 2. \sum_{k=0}^{\infty }\left ( \frac{2k^{2}+k+1}{4k^{2}+2} \right Determine if the series is diverges or converges and state which test is used. (a)...
Dec 6, 2009 #8 denverdoc 961 0 Degrees K is customary but the caclulation should be the same. The result falls squarely in the range cited for India rubber. Dec 6, 2009 #9 Psywing 5 0 Is that right? Well, I have no idea what type of rubber it is. So, I guess I'll...
Determine k, so that K^(2)+4k+8, 2k^(2)+3k+6 and 3k^(2)+4k+4 are three consecutive terms of an AP.
1. \sum_{k = 1}^\infty \frac{(-1)^{k +1} l^k}{(k +2)!}\2.\sum_{ k = 1}^\infty \frac{\sin{ \frac{k\pi}{2}{k^4}\3.\sum_{k = 1}^\infty (2 - \sqrtk{k})^{3k} Determine whether the following series ...
8.9K An infinite series is the sum of terms in an infinitely long sequence, but taking the sum of terms in a finite portion of the sequence is called a partial sum. Explore these two concepts through examples of five types of series: arithmetic, geometric, ha...
Step by step video & image solution for Determine k so that k^2 +4k +8, 2k^2 + 3k+6, 3k^2+ 4k +4 are three consecutive terms of an A.P. by Maths experts to help you in doubts & scoring excellent marks in Class 10 exams.Updated on:21/07/2023 ...
Answer to: Determine all unit vectors v orthogonal to a = 3i + 4j + k, b = 6i + 10j + 3k. By signing up, you'll get thousands of step-by-step...