aAlCl3+bCu =cCuCl2+dAl Step 2: Create a System of Equations Create an equation for each element (Al, Cl, Cu) where each term represents the number of atoms of the element in each reactant or product. Al:1a +0b=0c+1dCl:3a +0b=2c +0dCu:0a+1b =1c +0d ...
aAl +bNaCl +cCuCl2=dAlCl3+fNaCl +gCu Step 2: Create a System of Equations Create an equation for each element (Al, Na, Cl, Cu) where each term represents the number of atoms of the element in each reactant or product. Al:1a +0b+0c=1d +0f+0gNa:0a+1b +0c...
aAl(OH)3+bCuCl2=cAlCl3+dCu(OH)2 Step 2: Create a System of Equations Create an equation for each element (Al, O, H, Cu, Cl) where each term represents the number of atoms of the element in each reactant or product. Al:1a +0b=1c +0dO:3a +0b=0c+2dH:3a +0...
aCu(OH)2+bAlCl3=cAl(OH)3+dCuCl2 Step 2: Create a System of Equations Create an equation for each element (Cu, O, H, Al, Cl) where each term represents the number of atoms of the element in each reactant or product. Cu:1a +0b=0c+1dO:2a +0b=3c +0dH:2a +0...
a = 3 (CuCl2) b = 2 (AlBr3) c = 3 (CuBr2) d = 2 (AlCl3) Step 4: Substitute Coefficients and Verify Result Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. ...
b = 3 (CuCl2) c = 3 (Cu(OH)2) d = 2 (AlCl3) Step 4: Substitute Coefficients and Verify Result Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. ...
Step 2: Create a System of Equations Create an equation for each element (Al, Cl, Cu, Br) where each term represents the number of atoms of the element in each reactant or product. Al:1a +0b=1c +0dCl:3a +0b=0c+2dCu:0a+1b =0c+1dBr:0a+2b =3c +0d ...
aAlCl3+bCuBr2=cCuCl2+dAlBr3 Step 2: Create a System of Equations Create an equation for each element (Al, Cl, Cu, Br) where each term represents the number of atoms of the element in each reactant or product. Al:1a +0b=0c+1dCl:3a +0b=2c +0dCu:0a+1b =1c +0dBr:0a+2...