用了std::format给我程序膨胀了4倍 | 前几天想图省事少写几个字符串输出,所以用了cpp20的std::format,写完之后vs一release编译,程序大小突然膨胀到250KiB,原来只有50KiB的,吓得我立刻开始排查,查过来发现是format导致的,写的这个应用比较重视尺寸,所以移除了format用回老写法了。 编辑于 2024-08-05 13:48・
std::stringformat(std::format_string<Args...>fmt, Args&&...args); (1)(since C++20) template<class...Args> std::wstringformat(std::wformat_string<Args...>fmt, Args&&...args); (2)(since C++20) template<class...Args> std::stringformat(conststd::locale&loc, ...
#include <format> #include <iostream> #include <iterator> #include <string> int main() { std::string buffer; std::format_to ( std::back_inserter(buffer), // < OutputIt "Hello, C++{}!\n", // < fmt "20" // < arg ); std::cout << buffer; buffer.clear(); std::format_to...
对于用户定义类型,格式说明由用户定义的 std::formatter 特化决定。 args... - 要格式化的参数 loc - 用于本地环境特定格式化的 std::locale 返回值保有格式化结果的 string 对象。 异常若fmt 对于提供的参数不是合法的格式字符串则抛出 std::format_error 。并且会传播任何格式化器所抛的异常。 注解...
#include "fmt/format.h" #include <fmt/core.h> #include <fmt/chrono.h> using namespace std::literals::chrono_literals; int main() { fmt::print("Hello, world!\n"); std::string s = fmt::format("The answer is {}.", 42); fmt::print(s); fmt::print("Default format: {} {}...
cppformat的核心在于其直观易懂的API设计。开发者可以通过简单的几行代码实现复杂的数据格式化任务。例如,想要打印一个带有千分位分隔符的整数,仅需一行代码即可完成:`std::cout << format("{:,}", number);`。这样的语法结构既保持了C++语言的一致性,又引入了现代编程语言中常见的模板字符串特性,使得代码更加...
std::string s = fmt::format("I'd rather be {1} than {0}.","right","happy");//s == "I'd rather be happy than right." Print chrono durations(run) #include<fmt/chrono.h>intmain() {usingnamespacestd::literals::chrono_literals;fmt::print("Default format: {} {}\n", 42s, ...
The corresponding std::basic_format_arg in the result is determined as below: if TD is bool or Context::char_type, the std::basic_format_arg stores t; otherwise, if TD is char and Context::char_type is wchar_t, the std::basic_format_arg stores static_cast<wchar_t>(static_cast<...
{conststd::stringi0 ="Hello CppMiniToolkit"; std::stringr0 =StandardLibrary::Format(i0.c_str()); EXPECT_EQ(r0, i0);conststd::stringi1 ="Hello CppMiniToolkit {0}"; std::stringr1 = StandardLibrary::Format(i1.c_str(),1024); ...
{23stringstr;24StandardLibrary::FormatTo(str,"{0}--#--{1,8}--#--{2}",100, -40.2f,"String");25StandardLibrary::FormatTo(str,"{0}--#--{1,8}--#--{1}",100, -40.2f);26StandardLibrary::FormatTo(str,"{0}--#--{1,8}--#--{3}",100, -40.2f, std::string("xxx"));...