Step by step video, text & image solution for यदि alpha = (pi)/(7) हो, तो ((1)/(cos alpha) + (2 cos alpha)/(cos 2 alpha)) का मान ज्ञात कीजिए | by Maths experts to help
解析 11. 若$$ \cos \alpha = - \frac { 1 } { 3 } $$,则 $$ \frac { \cos ( 2 \pi - \alpha ) \sin ( \pi + \alpha ) } { \sin ( \frac { \pi } { 2 } + \alpha ) \tan ( 3 \pi - \alpha ) } = \frac { - \frac { 1 } { 3 } } { } $...
{ \sqrt { 5 } } { 3 } $$,且$$ \alpha \in $$ $$ ( - \frac { \pi } { 2 } , 0 ) $$,所以$$ \sin \alpha = - \sqrt { 1 - \cos ^ { 2 } \alpha } = - \frac { 2 } { 3 } $$ 所以$$ \sin ( \pi - \alpha ) = \sin \alpha = - \frac ...
Step by step video & image solution for यदि (If) alpha = (pi)/(3), तो सिद्ध कीजिए कि cos alpha. cos 2 alpha. cos 3 alpha. cos 4 alpha. cos 5alpha. cos 6alpha = (-1)/(16) by Maths experts to help you in doubts & scoring ex...
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Step by step video & image solution for यदि alpha+beta=(pi)/(2),तो सिद्ध कीजिए कि (cosalpha+isinalpha)(cosbeta+isinbeta)=i by Maths experts to help you in doubts & scoring excellent marks in Class 11 exams.Updated on:21/07/2023 ...
【题目】若$$ \cos ( 2 \pi - \alpha ) = \frac { 1 } { 2 } , \alpha \in ( - \frac { \pi } { 2 } , 0 ) $$则$$ \cos ( \alpha - \frac { 3 \pi } { 2 } ) = 0 $$ A.$$ \frac { \sqrt { 3 } } { 2 } $$ B. -$$ \frac { \sqrt { ...
答案见上B【解析】∵$$ \cos ( 2 \pi - \alpha ) = \cos \alpha = $$ $$ \frac { \sqrt { 5 } } { 3 } , \alpha \in ( - \frac { \pi } { 2 } , 0 ) $$ ∴$$ \sin \alpha = - \sqrt { 1 - \cos ^ { 2 } \alpha } = - \frac { 2 } { 3 ...
If alpha is a root of 25 cos^(2)theta + 5 cos theta - 12 =0, (pi)/(2) lt alpha lt pi , then sin 2alpha is equal to View Solution Iftanα=2and0<α<π2then prove thatx=a,π+αare the solution of the equationtan(2α−x)tan(2α+x)=11that lies between 0 and2π ...
20.解:(1)由已知$$ \cos \alpha = - \frac { 3 } { 5 } $$ ∴$$ \cos ( \frac { \pi } { 2 } + \alpha ) = - \sin \alpha = \frac { 4 } { 5 } $$ (2)$$ f ( \alpha ) = \frac { - \tan \alpha \sin \alpha \cdot \cos \alpha } { - \cos ...