在Power方法内部,使用Math.Pow方法计算底数的指数次幂,并返回结果。 在Main方法中,我们定义了一个底数baseNumber和一个指数exponent,然后调用Power方法计算结果,并将结果打印到控制台。 运行此代码,你应该会看到输出: text 2的 3 次方等于 8 这表明我们的方法正确地计算了一个数的k次方幂。
#include <iostream> #include <cmath> int main() { double x = 2.0; // 幂(Power) double power = std::pow(x, 3); std::cout << "x^3: " << power << std::endl; // 输出:x^3: 8 // 三角函数(Trigonometric Functions) double sin_x = std::sin(x); double cos_x = std::...
(the significand) by 2 raised to the power of exp (the exponent) double param, result; int n; param = 0.95; n = 4; result = std::ldexp(param, n); printf("%f * 2^%d = %f\n", param, n, result); // 0.95 * 2^4 = 15.2 } { // std::exp2: Returns the base-2 ...
double power = pow(num, 2); // 计算2次幂 // 输出square为1.732051,power为9 ``` 三、总结 以上就是关于cmath函数库中一些常用的数学函数的介绍,这些函数是编写计算程序时非常有用的。需要注意的是,在使用cmath函数库时,应该尽可能地选择合适的函数,这样可以提高程序的效率和可读性。©...
template<typename _Tp> _Tp __cmath_power(_Tp, unsigned int); inline double abs(double __x) { return __builtin_fabs(__x); } inline float abs(float __x) { return __builtin_fabsf(__x); } inline long double abs(long double __x) ...
{ // std::ldexp: Returns the result of multiplying x (the significand) by 2 raised to the power of exp (the exponent) double param, result; int n; param = 0.95; n = 4; result = std::ldexp(param, n); printf("%f * 2^%d = %f\n", param, n, result); // 0.95 * 2^4 =...
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# 需要导入模块: import cmath [as 别名]# 或者: from cmath importpolar[as 别名]def__pow__(self, power):ifpower ==1:returnselfifpower ==-1:returnPauliString(qubit_pauli_map=self._qubit_pauli_map, coefficient=self.coefficient**-1)ifisinstance(power, (int, float)): ...
/**@fileinclude/cmath *ThisisaStandardC++Libraryfile.Youshould@c#includethisfile *inyourprograms,ratherthananyofthe"*.h"implementationfiles. * *ThisistheC++versionoftheStandardCLibraryheader@cmath.h, *anditscontentsare(mostly)thesameasthatheader,butareall *containedinthenamespace@cstd(exceptfornames...
pow(x, y) Returns the value of x to the power of y remainder(x, y) Return the remainder of x/y rounded to the nearest integer remquo(x, y, z) Calculates x/y rounded to the nearest integer, writes the result to the memory at the pointer z and returns the remainder. rint(x) ...