启动Tomcat报错：classpathresourcecannotbeopened 启动Tomcat报错：classpathresourcecannotbeopened 直接原因：WEB-INF/classes下没有⽂件，即eclipse项⽬⽂件没有发布到Tomcat的⽂件夹。根本原因：项⽬的Java Build Path /Libraries ⾥tomcat 和jre引⽤失效，重新添加即可。PS：查看eclipse的Problems 窗⼝的错误提⽰，有助于快速确认错误...
class path resource [config/spring/springmvc.xml] cannot be opened because it does not exist 意思:类路径资源[springmvc.xml文件]无法打开,因为它不存在 分析:找不到我的springmvc.xml,在下面web.xml中是我引用路径,网上找到问题classpath指向路径不是resource路径,所以一直找不到我的xml文件, classpath:到...
我实验了一遍 --java265 class path resource [classpath:xxx.docx] cannot be opened because it does not exist class path resource [classpath:xxx.docx] cannot be opened because it does not exist 这个报错是文件读取不到。 解决办法: //本地读取: File tmpFile = null; try { tmpFile = ResourceU...
class path resource [applicationContext.xml] cannot be opened because it does not exist 翻译：没有找到你的 .xml 配置⽂件 原因 在Test测试类中我使⽤的是：ApplicationContext ctx = new ClassPathXmlApplicationContext("applicationContext.xml");获取配置⽂件。ClassPathXmlApplicationContext()⽅法是在...
failed; nested exception is org.springframework.core.NestedIOException: Failed to parse mapping resource: 'class path resource [classpath*:/mapper/**.xml]'; nested exception is java.io.FileNotFoundException: class path resource [classpath*:/mapper/**.xml] cannot be opened because it does not...
java.io.FileNotFoundException: class path resource [foo.txt] cannot be opened because it does not exist 问题原因 文件只在源代码中,不在target文件夹中,而classPathResource.getInputStream()是读编译后的文件,不是源代码文件: 解决方案 rebuild project(也可以先把target删了再rebuild),确保target中有相关...
错误：class path resource [config/spring/springmvc.xml] cannot be opened because it does not exist 错误原因：找不到我的springmvc.xml，在下⾯web.xml中是我引⽤路径，⽹上找到问题classpath指向路径不是resource路径，所以⼀直找不到我的xml⽂件， classpath:到你的class路径中查找⽂...
* @return the input stream for the underlying resource (must not be {@code null}) * @throws IOException if the stream could not be opened * @see org.springframework.mail.javamail.MimeMessageHelper#addAttachment(String, InputStreamSource) ...
上图这种写法报错: java.io.FileNotFoundException: class path resource [classpath:quartz.properties] cannot be opened be 在上图箭头1处,怎么改写才能读取箭头2处的资源文件?spring 有用关注2收藏 回复 阅读8.7k 3 个回答 得票最新 DreamEvil 42017 发布于 2017-01-05 把classpath去掉。 bean.setLocation...
= null) { is = this.classLoader.getResourceAsStream(this.path); } else { is = ClassLoader.getSystemResourceAsStream(this.path); } if (is == null) { throw new FileNotFoundException(getDescription() + " cannot be opened because it does not exist"); } return is; } 所以类获取资源的...