Ca(s) + 4H2SO4(aq) → CaSO4 + 2H2以上方程式的配平是错误的.因为左边有 4x2 = 8 个 H,右边有 2x2 = 4 个 H,两边的 H 数目不同.配平的步骤(1) 写下未配平的方程式.Ca(s) + H2SO4(aq) → CaSO4 + H2(2) 配平 Ca : 首先把 Ca 和 CaSO4 的系数定位 1,使两边的 Ca 数目均等...
H2SO4(aq)→ 2H+(aq) + SO42-(aq) 2H+(aq) + SO42-(aq) + Ca(s) = CaSO4(s) + 2H(g) Spectator Ions Spectator ions are ions that do not take part in the reaction. They are removed from the complete ionic equation to get the net ionic equation.Net...
答案见上【解析】(1)若三颈瓶中先加入硫酸溶液,向其中滴加Na2SO3溶液, 呈酸性,则易生成SO2导致 Na_2SO_3 的利用率减小,故分液漏斗中的 溶液是H2SO4溶液;MnO2被 SO_3^(2-) 还原为 Mn2+的离子方程式为 MnO_2+SO_3^(2-)+2H^+=Mn^(2+)+SO_4^(2-)+H_2O (2)CaF2(s)+Mg2+(aq)=MgF2(s...
H2SO4(aq)→2H+(aq)+ SO42-(aq) 2H+(aq)+ SO42-(aq)+ Ca(s)= CaSO3(s)+ H2O(l) Spectator Ions Spectator ions are ions that do not take part in the reaction. They are removed from the complete ionic equation to get the net ionic equation. ...
D.反应Ba2+(aq)+CaSO4(s)?BaSO4(s)+Ca2+(aq)的平衡常数K=c(Ca2+)c(Ba2+)c(Ca2+)c(Ba2+)=Ksp(CaSO4)Ksp(BaSO4)Ksp(CaSO4)Ksp(BaSO4). 解答 解:A.向a点的溶液中加入等物质的量固体Na2SO4或Ca(NO3)2,抑制固体溶解的作用相同,则析出的沉淀量相同,故A错误;B.曲线上的点为平衡点,c为...
CaSO4(s) H2O(l) Cl-(aq)ΔH4=dKJ/mol A. 随着吸收反应的进行,吸收剂溶液的pH逐渐减小 B. 反应①、②均为氧化还原反应 C. 反应Ca(OH)2(aq)+H2SO4(aq)=CaSO4(s)+2H2O(1)的ΔH=-ckJ/mol D. d=a+b+c 相关知识点: 试题来源: 解析 A-ckJ/mol,C错误;D.根据盖斯定律可知④=① ②...
H2SO4(aq)→2H+(aq)+ SO42-(aq) Ca(s)+2H+(aq)+ SO42-(aq)= H2(g)+ CaSO4(s) Spectator Ions Spectator ions are ions that do not take part in the reaction. They are removed from the complete ionic equation to get the net ionic equation. ...
(5)CaSO微溶于水,溶液中存在沉淀溶解平衡 Ca SO_4(s)⇌Ca^(2+)(aq)+SO_4^2 4(aq),故SO24有残留; 加入BaCO3转化为更难溶的BaSO,从而可进一步脱硫,离 子方程式为 BaCO_3+SO^2 4 +2H_3PO_4-BaSO_4+CO_2↑+H_2O+2 H2PO 4 (6)根据题意,H3PO4滴定终点的产物为HPO2,故H3PO 与NaOH的...
H2SO4(aq)→2H+(aq)+ SO42-(aq) 2H+(aq)+ SO42-(aq)+ Ca(s)= CaSO4(s)+ H2(g) Spectator Ions Spectator ions are ions that do not take part in the reaction. They are removed from the complete ionic equation to get the net ionic equation. ...
用稀硫酸洗涤BaSO4,沉淀损失小 BaSO4(s) Ba2+(aq) + SO42-(aq) 有机物A的分子式为C9H10O2,A在光照条件下生成的一溴代物B,可发生如下转化关系(无机产物略): 其中K物质与氯化铁溶液发生显色反应,且环上的一元取代物只有两种结构。 已知:①当羟基与双键碳原子相连时,易发生如下转化:RCH=CHOH→R...